The force-couple system shown can be replaced by a single equivalent couple CR. Determine CR. Can be done in two ways: using the fact that the 80 N can be split into 50+30, we have a 50 N-forces couple and a 30 N-forces couple and the 15 Nm couple.Then add the moments. OR simply compute moments about any point, let us use B. 720 mm 80 N M80 0.48k × (–80i) -38.4j 480 mm M30 15000 N mm M50 -0.72j × 50i = 36k 50 N MGiven -15j 30 N CR -53.4j + 36k Nm

The force-couple system shown can be replaced by a single equivalent couple CR. Determine CR. Can be done in two ways: using the fact that the 80 N can be split into 50+30, we have a 50 N-forces couple and a 30 N-forces couple and the 15 Nm couple.Then add the moments. OR simply compute moments about any point, let us use B. 720 mm 80 N M80 0.48k × (–80i) -38.4j 480 mm M30 15000 N mm M50 -0.72j × 50i = 36k 50 N MGiven -15j 30 N CR -53.4j + 36k Nm

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter2: Basic Operations With Force Systems

Section: Chapter Questions

Problem 2.80P: The figure shows one-half of a universal coupling known as the Hooke's joint. The coupling is acted...

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The figure shows one-half of a universal coupling known as the Hooke's joint. The coupling is acted on by the three couples shown: (a) the input couple consisting of forces of magnitude P, (b) the output couple C0, and (c) the couple formed by bearing reactions of magnitude R. If the resultant of these couples is zero, compute R and C0 for P=750lb.
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