The form of the partial fraction decomposition of a rational function is given below.16 – (x² + 10x)Вх + С+x2 +4A%3D(x + 2)(x² + 4)x +2A =B =C =Now evaluate the indefinite integral.16 – (x2 + 10x)-dx =|Tx+ 2)(x² + 4)

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The form of the partial fraction decomposition of a rational function is given below. 16 – (x² + 10x) Вх + С + x2 + 4 A %| (x + 2)(x² + 4) x +2 A = B = C = Now evaluate the indefinite integral. [ 16 – (x² + 10x) dx = - (x+ 2)(x² + 4)

The form of the partial fraction decomposition of a rational function is given below. 16 – (x² + 10x) Вх + С + x2 + 4 A %| (x + 2)(x² + 4) x +2 A = B = C = Now evaluate the indefinite integral. [ 16 – (x² + 10x) dx = - (x+ 2)(x² + 4)

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter5: Systems Of Equations And Inequalities

Section: Chapter Questions

Problem 15T

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Question

The form of the partial fraction decomposition of a rational function is given below.
16 – (x² + 10x)
Вх + С
+
x2 +4
A
%3D
(x + 2)(x² + 4)
x +2
A =
B =
C =
Now evaluate the indefinite integral.
16 – (x2 + 10x)
-dx =
|Tx+ 2)(x² + 4)

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