The form of the partial fraction decomposition of a rational function is given below. A = B = C= Now evaluate the indefinite integral. 10x² 18x +36 2)(-²0) -dx 10x² + 18x + 36 (x+3)(x² + 9) = A x + 3 + Bx + C x² +9
The form of the partial fraction decomposition of a rational function is given below. A = B = C= Now evaluate the indefinite integral. 10x² 18x +36 2)(-²0) -dx 10x² + 18x + 36 (x+3)(x² + 9) = A x + 3 + Bx + C x² +9
Chapter8: Sequences, Series,and Probability
Section: Chapter Questions
Problem 7CT
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![The form of the partial fraction decomposition of a rational function is given below.
A
=
B=C=
Now evaluate the indefinite integral.
10x² + 18x + 36
(x+3)(x² +9)
-dx
10x² + 18x + 36
(x+3)(x² +9)
A
x + 3
+
Bx + C
x² +9](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F952a0a26-688e-4b5b-af3d-b303dcbe5478%2F1784cae3-f85e-44f5-8d90-c56eb4886293%2F1rqgvif_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The form of the partial fraction decomposition of a rational function is given below.
A
=
B=C=
Now evaluate the indefinite integral.
10x² + 18x + 36
(x+3)(x² +9)
-dx
10x² + 18x + 36
(x+3)(x² +9)
A
x + 3
+
Bx + C
x² +9
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