Question
Asked Dec 2, 2019

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole.  How many carbon atoms are in 2.00 g of butane?

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Expert Answer

Step 1

Given data here,

The formula of butane is C4H10.

The molecular weight of butane is 58.1 g/mol.

so, the calculation of number of moles of butane in present in 2.00 g is as follows: 

amount of butane
number of moles of butane
molecular mass butane
2.00g
58.1g/mol
=0.0344 mol
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amount of butane number of moles of butane molecular mass butane 2.00g 58.1g/mol =0.0344 mol

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Step 2

One mole of butane contains 6.022×1023 molecules.

The calculation of the number of molecules present in 0.0344 moles of butane is as follows:

1 mole of butane 6.022 x 10"mole cule
0.0344 moles of butane 0.0344 x6.022 x 102molecule
=2.07x102molecule
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1 mole of butane 6.022 x 10"mole cule 0.0344 moles of butane 0.0344 x6.022 x 102molecule =2.07x102molecule

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Step 3

one molecule of butane contains 4 atoms of carbon.

The calculation of number of ...

1 molecule 4 carbon atoms
2.07x102 molecule 4x2.07x102 carbon atoms
=8x102 carbon atoms
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1 molecule 4 carbon atoms 2.07x102 molecule 4x2.07x102 carbon atoms =8x102 carbon atoms

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