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The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³): T = 16.574. dT = 1 0.52754. 1 V² 0.3879 P + 12.187 V P. (a) Find the temperature T and differential dT if the volume is 34 dm³ and the pressure is 0.75 atmosphere. T= (b) Use your answer to part (a) to estimate how much the pressure would have to change if the volume increased by 2.5 dm³ and the temperature remained constant. change in pressure =

The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³): T = 16.574. dT = 1 0.52754. 1 V² 0.3879 P + 12.187 V P. (a) Find the temperature T and differential dT if the volume is 34 dm³ and the pressure is 0.75 atmosphere. T= (b) Use your answer to part (a) to estimate how much the pressure would have to change if the volume increased by 2.5 dm³ and the temperature remained constant. change in pressure =

College Algebra
College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter3: Polynomial Functions
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The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³): dT T 16.574. = 1 V 0.52754. 1 V2 (a) Find the temperature T and differential dT if the volume is 34 dm³ and the pressure is 0.75 atmosphere. T = 0.3879 P + 12.187 V P. (b) Use your answer to part (a) to estimate how much the pressure would have to change if the volume increased by 2.5 dm³ and the temperature remained constant. change in pressure =
Transcribed Image Text:The gas equation for one mole of oxygen relates its pressure, P (in atmospheres), its temperature, T (in K), and its volume, V (in cubic decimeters, dm³): dT T 16.574. = 1 V 0.52754. 1 V2 (a) Find the temperature T and differential dT if the volume is 34 dm³ and the pressure is 0.75 atmosphere. T = 0.3879 P + 12.187 V P. (b) Use your answer to part (a) to estimate how much the pressure would have to change if the volume increased by 2.5 dm³ and the temperature remained constant. change in pressure =
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