The growth rate of a fungus varies over the course of one day. You find that the size of the fungus is given as a function of time by: a. L(t) = 3.6t + 1.2 cos(2nt/24) where t is the time in hours, and L(t) is the size in millimeters. Calculate the growth rate dL/dt. O A. dL/dt = 3.6 - sin(t) O B. dL/dt = 3.6 + 1.2 sin(2nt/24) O C. dL/dt = 3.6 – 1.2 sin(2rt/24) >O D. dL/dt = 3.6 – sin(2nt/24) b. What is the largest growth rate of the fungus? Please round to 3 decimal places.

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