The Hall Effect provided evidence that negative charges were responisble for moving in a circuit. In this problem we will walk through the process of this experiment. a) First we need to generate a uniform magnetic field. We can do this by using a solenoid. Calculate the magnetic field at the center of a solenoid if its has a length of 0.5 meters, 1000 loops, and a 600A current folwing through it. b) We will now place a piece of conducting metal inside the solenoid. We will run a current of through this piece of metal; assume that the drift velocity due to this current is 4 × 10−2 m/s. Calculate the magnetic force on the individual particles (q = 1.6 × 10−19 C) that make up the current in the presence of the magnetic field from part a). c) Assume the magnetic field from part a) is pointing into the page (- z direction) and the current from part b) is pointing to the right (+x direction). Using the right hand rule determine the direction of the force a negative charge would feel. Remember if the current is flowing to right, negative charges would be moving to the left. d) You will now measure the voltage across the piece of metal. The sign of the voltage will tell you whethere positive or negative charges are moving. Assume that the distance between the two points where you measure the voltage is 0.1 meters. You will use the same velocity that was given to you in part b). Calculate the voltage you should measure. Hint: You will need to balance the electric and magnetic forces.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Magnetic Forces And Magnetic Fields

Section: Chapter Questions

Problem 66P: The Hall effect finds important application in the electronics industry. It is used to find the sign...

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The Hall Effect provided evidence that negative charges were responisble for moving in a circuit. In this problem we will walk through the process of this experiment. a) First we need to generate a uniform magnetic field. We can do this by using a solenoid. Calculate the magnetic field at the center of a solenoid if its has a length of 0.5 meters, 1000 loops, and a 600A current folwing through it. b) We will now place a piece of conducting metal inside the solenoid. We will run a current of through this piece of metal; assume that the drift velocity due to this current is 4 × 10−2 m/s. Calculate the magnetic force on the individual particles (q = 1.6 × 10−19 C) that make up the current in the presence of the magnetic field from part a). c) Assume the magnetic field from part a) is pointing into the page (- z direction) and the current from part b) is pointing to the right (+x direction). Using the right hand rule determine the direction of the force a negative charge would feel. Remember if the current is flowing to right, negative charges would be moving to the left. d) You will now measure the voltage across the piece of metal. The sign of the voltage will tell you whethere positive or negative charges are moving. Assume that the distance between the two points where you measure the voltage is 0.1 meters. You will use the same velocity that was given to you in part b). Calculate the voltage you should measure. Hint: You will need to balance the electric and magnetic forces.

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