(The hammer blow) Let p(x) = 0 and √(x) = 1 for [x] < a and (x) = 0 for |x| ≥a. Sketch the string profile (u versus x) at each of the successive instants t = a/2c, a/c, 3a/2c, 2a/c, and 5a/c. [Hint: Calculate ex+ct = 1/10 ²² 2c x-ct u(x, t) = (s) ds = = 1 -{length of (x- ct, x + ct)n(-a, a)}. 2c Then u(x, a/2c) = (1/2c) {length of (x -a/2, x + a/2)^(-a, a)}. This takes on different values for [x] < a/2, for a/2 < x < 3a/2, and for x > 3a/2. Continue in this manner for each case.]

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 12T
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[Second Order Equations] How do you solve this question?

5. (The hammer blow) Let p(x) = 0 and (x) = 1 for [x] < a and
(x) = 0 for |x| ≥ a. Sketch the string profile (u versus x) at each of
the successive instants t = :a/2c, a/c, 3a/2c, 2a/c, and 5a/c. [Hint:
Calculate
1
cx+ct
u(x, t) = 4 (5
2c
x-ct
(s) ds
=
1
-{length of (x- ct, x + ct)^(-a, a)}.
2c
Then u(x, a/2c) = (1/2c) {length of (x − a/2, x + a/2)^(-a, a)}.
This takes on different values for |x| < a/2, for a/2 < x < 3a/2, and
for x > 3a/2. Continue in this manner for each case.]
Transcribed Image Text:5. (The hammer blow) Let p(x) = 0 and (x) = 1 for [x] < a and (x) = 0 for |x| ≥ a. Sketch the string profile (u versus x) at each of the successive instants t = :a/2c, a/c, 3a/2c, 2a/c, and 5a/c. [Hint: Calculate 1 cx+ct u(x, t) = 4 (5 2c x-ct (s) ds = 1 -{length of (x- ct, x + ct)^(-a, a)}. 2c Then u(x, a/2c) = (1/2c) {length of (x − a/2, x + a/2)^(-a, a)}. This takes on different values for |x| < a/2, for a/2 < x < 3a/2, and for x > 3a/2. Continue in this manner for each case.]
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