The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule. Solo: given Nape kcal/l Heat of melting ice at 1 atm pressure = 1.4363 kcal 2 = 1.4363 kcal/mole mae Volume of ice = 0·0196 Its " water = 0.018 lts. @ work done is define as w=pdv » w= P. CVPTV₂ W = 1 (0·018-010196) W = 0·0016 Cal Ans суток

The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of water is 0.018 liter. If 1 mole of ice is melted under these conditions, what will be a. The work done in cal? b. The change in internal energy in cal? c. The change in entropy in cal? Note that 1 literxatmosphere is equal to 101.325 joule. Solo: given Nape kcal/l Heat of melting ice at 1 atm pressure = 1.4363 kcal 2 = 1.4363 kcal/mole mae Volume of ice = 0·0196 Its " water = 0.018 lts. @ work done is define as w=pdv » w= P. CVPTV₂ W = 1 (0·018-010196) W = 0·0016 Cal Ans суток

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter22: Heat Engines, Entropy, And The Second Law Of Thermodynamics

Section: Chapter Questions

Problem 22.2OQ: Assume a sample of an ideal gas is at room temperature. What action will necessarily make the...

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