The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22.5 m/s is h = 2 + 22.5t – 4.9t2 after t seconds. (a) Find the velocity (in m/s) after t seconds. v(t) = 22.5 – 9.8t v Find the velocity (in m/s) after 2 seconds and after 4 seconds. v(2) = 2.9 m/s v(4) = -16.7 m/s (b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height? v(t) = -0.0008 x m/s When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.) 2.29

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The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22.5 m/s is h = 2 + 22.5t – 4.9t after t seconds.
(a) Find the velocity (in m/s) after t seconds.
v(t) = | 22.5 – 9.8t
Find the velocity (in m/s) after 2 seconds and after 4 seconds.
v(2)
= 2.9
m/s
v(4) = -16.7
m/s
(b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height?
v(t) = -0.0008
X m/s
When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.)
2.29
X S
Transcribed Image Text:The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22.5 m/s is h = 2 + 22.5t – 4.9t after t seconds. (a) Find the velocity (in m/s) after t seconds. v(t) = | 22.5 – 9.8t Find the velocity (in m/s) after 2 seconds and after 4 seconds. v(2) = 2.9 m/s v(4) = -16.7 m/s (b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height? v(t) = -0.0008 X m/s When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.) 2.29 X S
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