The highway engineer of a certain roadconstruction decided to use a radius of 100 m.in laying out a simple curve having an angle ofintersection of 36'20', The stationing of thevertex is 30 + 375.20 after verifying the actualconditions of the proposed route, it was foundout that the P.T. should be moved out in aparallel tangent having a perpendiculardistance of 10 meters with the angle ofintersection remaining the same while thecurve shall have the same P.C.O Compute the new tangent distance.@ Compute the new radius.of curve.3 Compute the stationing of new P.T.

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Answered: The highway engineer of a certain road…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Determine the values and stationing (sta. PT) for a compound curve to be placed on an exist loop of a freeway. The stationing of the loop construction will start at the point the taper departs the freeway with a station of 10+00. The PI of the compound curve will begin 2,700ft after the taper starts. The first curve has a radius of 2,400ft and a deflection angle of 33deg 45’ and the second curve has a radius of 1,900ft and a deflection angle of 25deg 15’.
A +2.5% grade meets a -1.75% grade at the station 44+25 and elevation 386.96 ft, the length of curve is 800 feet (8 stations). (1) Provide the stakeout for full stations using parabolic method STATION X g1 X (g2-g1) X2 2L Y (Elevation) PVT = PVC = (2) Determine the station and elevation at the high point of the curve
An unsymmetrical vertical parabolic curve of a certain highway with a length of140m has its vertex V at station 4+300 and elevation 56.00m. The back tangenthas a grade of 8% and a length of 90m and its forward tangent with a -5% gradeand a length of 50m. Compute the elevations of the curve at each 10-mstationing and tabulate the results.
Design the curve, of An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. GIVEN DIMENSIONS ON THE ATTACHED PICTURE
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The design speed for a two-lane highway (lane width=12 ft.) is 60 mph. The localjurisdiction governs 8% superelevation. The central angel of the curve is 40 degrees. The PI station is at 452+50.What is the curve radius to the travel path (R୚)? What is the curve radius (R)? What is the curve length (L)? What isthe station of PC? What is the station of PT? What is the SSD? How many feet must be cleared from the lane'sshoulder edge to provide adequate stopping sight distance?
1. The curve of a diversion road has a tangent “AB” which is directed due North and theother tangent “BC” is having a bearing of ?70°?. Point “A” is located at P.C. whosestationing is 12 + 600. The degree of curve using arc-basis is 5°.a. Compute the radius of the curve.b. Compute the long chord of the curve.c. What is the stationing at P.I.?d. Compute for the middle ordinate.e. Compute for the external distance.
NEED ASAP A vertical curve has its highest point at a distance 48 meters from point PT. The curve is having two tangents having a grade of +6% and -4% which intersects at point Pl. The curve passes thru point A at station 25+140. The elevation of point Pl is 100 meters above sea level at 25+160 station. What is the elevation of the point of tangency in the curve?
A compound curve has the following properties: 1,= 25-degree, D,= 6.2-degree, 2= 36-degree, D2= |4.5-degree. Compute the stationing of PCC if PC is at station 10+430.
NEED ASAP A vertical curve has its highest point at a distance 48 meters from point PT. The curve is having two tangents having a grade of +6% and -4% which intersects at point Pl. The curve passes thru point A at station 25+140. The elevation of point Pl is 100 meters above sea level at 25+160 station. What is the maximum offset in meters?
a simpl3 curve has A radius of 1 0 0 meters and an angle of intersection of the tangents equal to 35°. It is required to change the curve such that the point of tangency should be moved out a distance of 10 meters without changing the direction of the tangents and the stationing of the point of curvature. Find the length of the new tangent. kindly input an illustration and complete sol'n that I can understand.
An equal tangent vertical curve is intended to connect grades of 4% and -3.9%. If this curve is to be a part of a highway designed with a PSD of 700ft, determine the minimum length (ft) of the vertical curve. Use exact solution (do not use the table). Round your answer to 3 decimal places.

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