11020)02020)The horizontal component of velocity remains . during a free-flight motion.102020)Soru 1Cevap kaydedildiLütfen birini seçin:11.2020)3,00 üzerindena, zerosture Lectuişaretlenmişb. increases with time12.11 2020)P Soruyu işaretleC. decreases with time(19 11 2020)>d. constant(25 11 2020)e. at 9.81 m/s29(26 11 2020)10 (27 11 2020)Sonraki sayfaOyranscn Mepartiment otBizi takip edin

During a free flight motion, the horizontal component of velocity will remain constant.

Answered: The horizontal component of velocity…

Engineering

Mechanical Engineering

The horizontal component of velocity remains. during a free-flight motion. Lütfen birini seçin: a. zero

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Activity Immediate Predecessor(s) Te VAR Slack A - 5 0.444 0 B - 2 0.111 4 C - 3 0.444 6.5 D A 7.5 0.25 0 E B 6.5 0.694 4 F C 8 0.111 6.5 G D, E 5 0.111 0 What is the critical path for the project described by this table? A. C-F B. B-E-G C. A-D-G D. A-B-C Click to select your answer.
1) An electric motor’s torque is a function of the speed at which it rotates. Many brushed AC motors have a linear toque curve as shown below. If the power output of the motor is equal to the torque (T) multiplied by the rotational speed in rad/s (w), what is the maximum power you can get out of the motor if the stall torque (Tstall) is 0.001 Nm and the no load speed (wno load) of 10,500 RPM? Give answer in Watts.
A wind turbine has the maximum power output at the rated speed of 12 m/s and a rotor diameter of 82 meters. The cut-in and cut-out speeds for this type of wind turbine are 4 m/s and 23 m/s, respectively. The table below shows the annual wind data near a potential site for setting up a wind farm using this type of wind turbine and the power coefficient of the wind turbine at the specific wind speed. The air density is 1.22 kg/m3. (a). What is the maximum power output of this wind turbine, assuming Betz limit? (b). What is the average power output if the wind turbine is installed at this site?. (c). What is the capacity factor of the wind turbine at this site? (d). If a wind farm consisting of 100 such wind turbines is built at the site, how much energy does this wind farm generate in a year (in the unit of kWh)? (e). Is this a good site for using this particular type of wind turbine?
Dusty air at a fertilizer plant flows through a 13% efficient cyclone and then through an ESP, The inlet air to the cyclone has a dust loading of 80 grains/cubic foot. In order to meet a standard of 98,5% collection efficiency for the fertilizer plant as a whole, what is the allowable concentration of dust (in grains/cubie foot) in the air that exits from the ESP?a. 0.15 gr/ft3 b 1.2 gr/ft3c. 21.6 gr/ft3 d. 58.4 gr/ft3
The horizontal force due to water acting on the bolt (Fh): Fh=ρ×A1×V1×V1--V2 Fh=1000×π4×0.0752×1.254×1.254+11.286( Fh)=69.472 This is the only part I did not understand how to get. Can you please explain more? I arrived with this equation, -P1A1 - P2A2 (cancelled since atmos. Pres.) +Fh = rho A1v1 (v2-v1) Why did P1A1 disappear in your solution? How did you come up with (v1 - - v2) ? What is the control volume? Why did you not do a summation of forces is equal to change in momentum but instead go immediately to getting the horizontal force acting on the bolt?
A vertical jet thru a nozzle supports a 150.90N weight. The velocity and diameter of the jet are 17.90m/s and 3.90 cm respectively. Find the distance of load from the nozzle in meters. Group of answer choices 13.79 31.79 17.93 71.39I need an answer for this asap :(
Differantial Equations
29 - Water is drawn from the bottom of a large tank filled with water open to the atmosphere. If the outlet velocity is 7.2 m/s, what could be the height of the water in the tank? a) 2.64m B) 4.38m NS) 3.65 m D) 5.46 m TO) 2.20m 30 - What would be the weight of an object with a mass of 100 kg in a place where the gravitational acceleration is 8 m/s²? a) 42.2 kgf B) 98.1 N NS) 800 N D) 9810 N TO) 196.2 N
The data provided by a company for the year 2020 – 2021 to carry out Break Even Analysis and provide them the results, complete analysis and suggestions. The data is as follows:Building rent 20000 R.O Every month instalments 30000 R.OThe estimated sales are 750000.0 R.OMaterial Cost / unit 15.0 R.OProduction cost / unit 8.0 R. OTransportation & other Costs / unit (Approx) 4.00 R. O Maintenance cost / unit 1.5 R. O Salary of the employees / unit 0.8 R.OMarketing and advertisement cost / unit 0.7 R. OEach unit is sold at price 35.0 R. O Construct the B.E.P chart on a graph sheet and indicate, B.E.P, M.o.S and also indicate the new B.E.P & M.o.S after the improvement measures has been taken (With different colours). Show the calculations for the following parameters separately before and after the measures taken.1. Determine the B.E.P2. Determine the profit 3. Margin of safety.Also write your decisions taken to improve the profits of the company and to reduce the B.E.P.
The following data were obtained during a test of six cylinder otto cycle engine. Speed 2000 rpm, bore 3.5 in stroke 3.75 in, specific fuel consumption base on brake hp.66 lbs. / bhp-hr, brake arm 1.05 ft. HHV of fuel 20000 Btu/lb, Brake Torque 133 ft-lb, friction torque 40 ft-lb room temperature 90 F. barometric pressure 14.7 psia Find:a.) BHP=b.) BMEP=c.) IMEP=d.) IHP=e.) BRAKE THERMAL EFFICIENCY=f.) INDICATED THERMAL EFFICIENCY=
Topic : Mixture Flow Problem A tank initially holds 100 gal of salt solution in which 50 Ib of salt has been dissolved. A pipe fills the tank with brine at the rate of 3 gpm, containing 2 lb of dissolved salt per gallon. Assuming that the mixture is kept uniform by stirring, a drain pipe draws out of the tank at 2pm. Find the amount of salt at the end of 30 minutes. Ans. 171.24 Ib
Can tutor explained the questions from d,e,f more clear on the step and if possible can it do by using the formula I had learnt so far which is s = Rθ v = Rω at = Rα T=2pi x square root(L/g) fn= 1/2pi x square root (k/m)