The hydrolysis of СІ (CH2)6C CH3 in 80% ethanol follows the first-order rate equation. The values of the specific reaction rate constants are as follows: t°C 0 25 35 45 k/s-1 : 1.06 X 10-5 3.19 x 10-4 9.86 x 10-4 2.92 x 10-3 (a) Plot log k against 1/T. (b) Calculate the activation energy, (c) Calculate the pre-exponential factor
The hydrolysis of СІ (CH2)6C CH3 in 80% ethanol follows the first-order rate equation. The values of the specific reaction rate constants are as follows: t°C 0 25 35 45 k/s-1 : 1.06 X 10-5 3.19 x 10-4 9.86 x 10-4 2.92 x 10-3 (a) Plot log k against 1/T. (b) Calculate the activation energy, (c) Calculate the pre-exponential factor
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter13: Rates Of Reaction
Section: Chapter Questions
Problem 13.22QP
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The hydrolysis of СІ (CH2)6C CH3 in 80% ethanol follows the first-order rate equation. The values of the specific reaction rate constants are as follows:
t°C 0 25 35 45
k/s-1 : 1.06 X 10-5 3.19 x 10-4 9.86 x 10-4 2.92 x 10-3
(a) Plot log k against 1/T. (b) Calculate the activation energy, (c) Calculate the pre-exponential factor.
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