The inductive step of an inductive proof shows that for k > 0, if E 2' = 2k+l – 1 then E 2 = 2*+2 j=0 In which step of the proof is the inductive hypothesis used? E 2 3(2*+1 – 1) + 2*+1 (Step 2) E, 2 + 2*+1 (Step 1) j=0 %3D = 2· 2k+1 – 1 (Step 3) = 2k+2 - 1 (Step 4) O Step 3 O Step 2 O Step 1 O Step 4

The inductive step of an inductive proof shows that for k > 0, if E 2' = 2k+l – 1 then E 2 = 2+2 j=0 In which step of the proof is the inductive hypothesis used? E 2 3(2+1 – 1) + 2+1 (Step 2) E, 2 + 2+1 (Step 1) j=0 %3D = 2· 2k+1 – 1 (Step 3) = 2k+2 - 1 (Step 4) O Step 3 O Step 2 O Step 1 O Step 4

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.4: Mathematical Induction

Problem 25E

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