Please answer the all questions to the 4th decimal points. Thank you! The joint probability mass function of X and Y is given byp(1, 1) = 0.05p(1, 2) = 0.1p(1, 3) = 0.05p(2, 1) = 0.1p(2, 2) = 0.25 p(2, 3) = 0.1p(3, 1) = 0.05 p(3, 2) = 0.1Р(3, 3) %3D 0.2(a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) =P(Y = 2|X = 2) =P(Y = 3|X = 2) =(b) Are X and Y independent? (enter YES or NO)(c) Compute the following probabilities:P(X +Y > 3) =P(XY = 3) =P(즉 > 2) =D

The joint probability mass function of X and Y is given by p(1, 1) = 0.05 p(1, 2) = 0.1 p(1, 3) = 0.05 p(2, 1) = 0.1 p(2, 2) = 0.25 p(2, 3) = 0.1 p(3, 1) = 0.05 Р(3, 2) %3D 0.1 p(3, 3) = 0.2 %3D (a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) = %3D P(Y = 2|X = 2) = %3D P(Y = 3|X ='2) = (b) Are X and Y independent? (enter YES or NO) (c) Compute the following probabilities: P(X +Y > 3) = %3D P(XY = 3) = |3D P(주 > 2) =D

The joint probability mass function of X and Y is given by p(1, 1) = 0.05 p(1, 2) = 0.1 p(1, 3) = 0.05 p(2, 1) = 0.1 p(2, 2) = 0.25 p(2, 3) = 0.1 p(3, 1) = 0.05 Р(3, 2) %3D 0.1 p(3, 3) = 0.2 %3D (a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) = %3D P(Y = 2|X = 2) = %3D P(Y = 3|X ='2) = (b) Are X and Y independent? (enter YES or NO) (c) Compute the following probabilities: P(X +Y > 3) = %3D P(XY = 3) = |3D P(주 > 2) =D

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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