Question
Asked Oct 13, 2019
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The length of the base of an isosceles triangle is 38.15 inches. Each base angle is 24.94. Find the length of each of the two equal sides of the triangle. (Hint: Divide
the triangle into two right triangles.)
The other two sides of the triangle have lengths of
(Simplify your answer. Type an integer or decimal rounded to the nearest hundredth as needed.)
inches.
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The length of the base of an isosceles triangle is 38.15 inches. Each base angle is 24.94. Find the length of each of the two equal sides of the triangle. (Hint: Divide the triangle into two right triangles.) The other two sides of the triangle have lengths of (Simplify your answer. Type an integer or decimal rounded to the nearest hundredth as needed.) inches.

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Expert Answer

Step 1

Let ABC be the isosceles triangle with base BC and equal sides AB and AC. Then BC=38.15 inches and angle ABC=angle ACB=24.94 degrees. Let AD be the perpendicular drawn from a to side BC . Since triangles ABD and ACD are congruent , so BD=DC, that is BD=BC/2=19.075 inches

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A C D

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Step 2

In triangle ABD ...

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BD cos(ZABC) АВ 19.075 cos(24.94 АВ 19.075 21.04 АВ : cos(24.94 AC AB 21.04inches

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Math

Trigonometry

Trigonometric Ratios