Question 26 The lengths of time (in years) it took a random sample of 32 former smokers to quit smoking permanently are listed. Assume the population standard deviation is 6.4 years. At α = 0.05, is there enough evidence to reject the claim that the mean timeit takes smokers to quit smoking permanently is 15 years? Complete parts (a) through (e).(a) Identify the claim and state the null hypothesis and alternative hypothesis.O A. Ho: μ> 15 (claim)Ha:μ≤15OD. Ho: μ≤ 15 (claim)Ha:μ>15(b) Identify the standardized test statistic. Use technology.Z= (Round to two decimal places as needed.)(c) Find the P-value. Use technology.P= (Round to three decimal places as needed.)10.6 13.5 7.713.4 20.8 11.421.2 19.7 17.113.3 15.5 19.8 18.2 20.9 O11.6 13.8 19.2 9.6 19.812.7 17.2 12.9 20.2 15.517.1 13.2 22.1 21.1 12.7 21.9 21.4 22.8OB. Ho: μ‡ 15 (claim)H₂:μ=15O E. Ho: μ = 15 (claim)Ha:μ#15OC. Ho: μ ≥ 15 (claim)Ha:μ< 15OC. Fail to reject Ho. There is not sufficient evidence to reject the claim that the mean time it takes smokers to quitsmoking permanently is 15 years.OF. Ho:μ> 15Ha: μ≤ 15 (claim)(d) Decide whether to reject or fail to reject the null hypothesis and (e) interpret the decision in the context of the original claim at the 5% level of significance.O B.A. Reject Ho. There is not sufficient evidence to reject the claim that the mean time it takes smokers to quit smokingpermanently is 15 years.Fail to reject Ho. There is sufficient evidence to reject the claim that the mean time it takes smokers to quit smokingpermanently is 15 years.O D. Reject Ho. There is sufficient evidence to reject the claim that the mean time it takes smokers to quit smokingpermanently is 15 years.

From the provided information,Population standard deviation (σ) = 6.4Sample size (n) = 32

The lengths of time (in years) it took a random sample of 32 former smokers to quit smoking permanently are listed. Assume the population standard deviation is 6.4 years. At a = 0.05, is there enough evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 15 years? Complete parts (a) through (e). (a) Identify the claim and state the null hypothesis and alternative hypothesis. OA. Ho: μ> 15 (claim) H₂:μs 15 OD. Ho: s15 (claim) H₂:μ> 15 (b) Identify the standardized test statistic. Use technology. z = (Round to two decimal places as needed.) (c) Find the P-value. Use technology. P= (Round to three decimal places as needed.) 10.6 13.5 7.7 13.3 15.5 19.8 18.2 20.9 13.4 20.8 11.4 11.6 13.8 19.2 9.6 19.8 21.2 19.7 17.1 12.7 17.2 12.9 20.2 15.5 17.1 13.2 22.1 21.1 12.7 21.9 21.4 22.8 OB. Ho: 15 (claim) H₂:μ=15 OE. Ho: = 15 (claim) H₂H15 (d) Decide whether to reject or fail to reject the null hypothesis and (e) interpret the decision in the context of the original claim at the 5% level of significance. O A. Reject Ho. There is not sufficient evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 15 years. OC. Fail to reject Ho. There is not sufficient evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 15 years. OC. Ho: μ ≥ 15 (claim) H₂H<15 OF. Ho: >15 H₂:μs 15 (claim) O B. Fail to reject Ho. There is sufficient evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 15 years. O D. Reject Ho. There is sufficient evidence to reject the claim that the mean time it takes smokers to quit smoking permanently is 15 years.

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter13: Probability And Calculus

Section13.3: Special Probability Density Functions

Problem 28E