Question
Asked Mar 25, 2019
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The loaded cab of an elevator has a mass of 3.10 × 103 kg and moves 240. m up the shaft in 21.0 s at constant speed. At what average rate does the force from the cable do work on the cab?

number______units_____?

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Expert Answer

Step 1

Given:  mass (m) = 3 × 103 kg

               distance (d) = 240 m

                 time (t) = 21 s

Find: Average rate at which force from the cable do work on the cab.

Step 2

Since, the elevator is moving at constant speed thus there i no net force.

So, T =  mg

        T = 3000 × 9.8 = 29400 = 29.4 kN

 

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Step 3

The work done by the tenion for...

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Work,Power and Energy

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