The lower limit is less than 0, so part two of the fundamental theorem of calculus cannot be applied. 6. (x) = is continuous on the interval [-2, 3] so part two of the fundamental theorem of calculus cannot be applied. (x) - is not continuous at x = -2, so part two of the fundamental theorem of calculus cannot be applied. There is nothing wrong with the equation. f(x) - is not continuous on the interval [-2, 3] so part two of the fundamental theorem of calculus cannot be applied.

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.3: Multiplying Monomials
Problem 6MRE
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Which part of this equation is wrong?

 

The lower limit is less than 0, so part two of the fundamental theorem of calculus cannot be applied.
6.
f(x)
is continuous on the interval [-2, 3] so part two of the fundamental theorem of calculus cannot be applied.
f(x)
is not continuous at x = -2, so part two of the fundamental theorem of calculus cannot be applied.
There is nothing wrong with the equation.
f(x)
is not continuous on the interval [-2, 3] so part two of the fundamental theorem of calculus cannot be applied.
Transcribed Image Text:The lower limit is less than 0, so part two of the fundamental theorem of calculus cannot be applied. 6. f(x) is continuous on the interval [-2, 3] so part two of the fundamental theorem of calculus cannot be applied. f(x) is not continuous at x = -2, so part two of the fundamental theorem of calculus cannot be applied. There is nothing wrong with the equation. f(x) is not continuous on the interval [-2, 3] so part two of the fundamental theorem of calculus cannot be applied.
3 6
dx
3
5
-2 X
2
I-2
12
Transcribed Image Text:3 6 dx 3 5 -2 X 2 I-2 12
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