The magnetic field of a proton is approximately like that of a circular current loop 0.650 × 10-15 m in radius carrying 1.05 × 104 A. An MRI machine is required to be able to manipulate these fields. Part (a) To see why an MRI utilizes iron to increase the magnetic field produced by a coil, calculate the current required in a 400 loop-per-meter circular coil 0.660 m in radius to produce a 1.20 T field (typical of an MRI instrument) at its center with no iron insert. Part (b) What is the field at the center of a proton? Notice how it compares to the field we used in the previous calculation.
The magnetic field of a proton is approximately like that of a circular current loop 0.650 × 10-15 m in radius carrying 1.05 × 104 A. An MRI machine is required to be able to manipulate these fields. Part (a) To see why an MRI utilizes iron to increase the magnetic field produced by a coil, calculate the current required in a 400 loop-per-meter circular coil 0.660 m in radius to produce a 1.20 T field (typical of an MRI instrument) at its center with no iron insert. Part (b) What is the field at the center of a proton? Notice how it compares to the field we used in the previous calculation.
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter29: Magnetic Fields
Section: Chapter Questions
Problem 29.13OQ: A magnetic field exerts a torque on each of the current-carrying single loops of wire shown in...
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The magnetic field of a proton is approximately like that of a circular current loop 0.650 × 10-15 m in radius carrying 1.05 × 104 A. An MRI machine is required to be able to manipulate these fields.
Part (a) To see why an MRI utilizes iron to increase the magnetic field produced by a coil, calculate the current required in a 400 loop-per-meter circular coil 0.660 m in radius to produce a 1.20 T field (typical of an MRI instrument) at its center with no iron insert.
Part (b) What is the field at the center of a proton? Notice how it compares to the field we used in the previous calculation.
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