The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass? A

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter4: Newton's Laws Of Motion
Section: Chapter Questions
Problem 91AP: The board sandwiched between two other boards in Figure P4.91 weighs 95.5 N. If the coefficient of...
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1. The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on
his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass?
Previous submissions:
40.95
kg
Transcribed Image Text:1. The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass? Previous submissions: 40.95 kg
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