# The manufacturer of a laser printer reports the mean number of pages a cartridge will print before it needs replacing is 12,225. Thedistribution of pages printed per cartridge closely follows the normal probability distribution and the standard deviation is 795 pages.The manufacturer wants to provide guidelines to potential customers as to how long they can expect a cartridge to last. Use AppendixB.3How many pages should the manufacturer advertise for each cartridge if it wants to be correct 90 percent of the time? (Round your zvalue to 2 decimal places and the final answer to the nearest whole number.)PagesNext>< Prev9 of 106:39 AM2 to search10/20/2019DELLF4PrtScrF8F5F12F6F7F9F10F11Delere

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Step 1

We are given,

X: Number of pages should the manufacturer advertise for each cartridge.

Which follows normal distribution.

Step 2

Population mean = μ =12,225

SD = σ = 795

First, we have to find z-value with a left-tail of 10% as we have given right tail as 90%.

Using z-table,

z = -1.2816

Step 3

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