The manufacturer of a low-calorie dairy drink wishes to compare the taste appeal of a new formula (formula B) with that of the standard formula (formula A). Each of four judges is given three glasses in random order, two containing formula A and the other containing formula B. Each judge is asked to state which glass he or she most enjoyed. Suppose that the two formulas are equally attractive. Let Y be the number of judges stating a preference for the new formula. 2.1.1 How can the mean and standard deviation be calculated (2). 2.2.2 Interpret the mean = 1.3333 and the standard deviation = 0.9428 of Y (2).

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
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2.1 Answer the below question:
The manufacturer of a low-calorie dairy drink wishes to compare the taste appeal of a new
formula (formula B) with that of the standard formula (formula A). Each of four judges is given
three glasses in random order, two containing formula A and the other containing formula B.
Each judge is asked to state which glass he or she most enjoyed. Suppose that the two formulas
are equally attractive. Let Y be the number of judges stating a preference for the new formula.
2.1.1 How can the mean and standard deviation be calculated (2).
2.2.2 Interpret the mean = 1.3333 and the standard deviation = 0.9428 of Y (2).
Transcribed Image Text:2.1 Answer the below question: The manufacturer of a low-calorie dairy drink wishes to compare the taste appeal of a new formula (formula B) with that of the standard formula (formula A). Each of four judges is given three glasses in random order, two containing formula A and the other containing formula B. Each judge is asked to state which glass he or she most enjoyed. Suppose that the two formulas are equally attractive. Let Y be the number of judges stating a preference for the new formula. 2.1.1 How can the mean and standard deviation be calculated (2). 2.2.2 Interpret the mean = 1.3333 and the standard deviation = 0.9428 of Y (2).
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