The maximum problem is not in standard form. Determine if the problem can be modified so as to be in standard form. If it can, wrie modified version. Maximize P= 3x1 + X2 + 8x3 subject to the constraints -X + x2 + x - 10 3x1 - 8x2 2 - 15 Xy s3 X1 20, x2 2 0, x3 20

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.8: Linear Programming
Problem 40E
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C.
Maximize P= 3x + x2 + 8x3 subject to the constraints
X1 + X2 + x3 s 10
-3x1 + 8x2 s 15
X3 <3
X1 2 0, x2 2 0, x3 2 0
od.
Maximize P = 3x1+ X2+ 8x3 subject to the constraints
X1- x2 -x3 s 10
-3x1 + 8x2 s 15
X3 <3
X1 2 0, x2 2 0, xX3 20
Oe.
Maximize P = 3x1 + x2 + 8x3 subject to the constraints
X1- X2 - X3 2 10
-3x1 + 8x2 2 15
X3 s3
X1 2 0, x2 2 0, xX3 20
Transcribed Image Text:C. Maximize P= 3x + x2 + 8x3 subject to the constraints X1 + X2 + x3 s 10 -3x1 + 8x2 s 15 X3 <3 X1 2 0, x2 2 0, x3 2 0 od. Maximize P = 3x1+ X2+ 8x3 subject to the constraints X1- x2 -x3 s 10 -3x1 + 8x2 s 15 X3 <3 X1 2 0, x2 2 0, xX3 20 Oe. Maximize P = 3x1 + x2 + 8x3 subject to the constraints X1- X2 - X3 2 10 -3x1 + 8x2 2 15 X3 s3 X1 2 0, x2 2 0, xX3 20
The maximum probiem is not in standard form. Determine if the problem can be modified so as to be in standard form. If it can, wri
modified version.
Maximize P= 3x1 + x2 + 8x3 subject to the constraints
-X1 + X2 + X3 - 10
3x1 - 8x2 2 - 15
s3
X1 2 0, x2 2 0, X3 2 0
Oa.
Maximize P = 3x1 + X2 + 8x3 subject to the constraints
%3!
-X1 + X2 + X3 2 - 10
-3x1 + 8x2 2 - 15
-X3 2 -3
X1 2 0, x2 2 0, X3 20
Ob. The maximum problem cannot be modified to be in standard form,
Transcribed Image Text:The maximum probiem is not in standard form. Determine if the problem can be modified so as to be in standard form. If it can, wri modified version. Maximize P= 3x1 + x2 + 8x3 subject to the constraints -X1 + X2 + X3 - 10 3x1 - 8x2 2 - 15 s3 X1 2 0, x2 2 0, X3 2 0 Oa. Maximize P = 3x1 + X2 + 8x3 subject to the constraints %3! -X1 + X2 + X3 2 - 10 -3x1 + 8x2 2 - 15 -X3 2 -3 X1 2 0, x2 2 0, X3 20 Ob. The maximum problem cannot be modified to be in standard form,
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