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The mean number of miles (in thousands) that a car's tire will function before needing replacement is 71; the standard deviation is 11 (also in thousands). Assume a normal distribution. a) If we test 49 tires, find the probabtility that the average miles (In thousands) before need of replacement is between 68.7 and 70.2. Round your answer to 4 decimal places. P(68.7 < # < 70.2) b) Is the assumption that the distribution is normal necessary in order for you to answer part a? O Yes ONo c) If a randomly-selected individual tire is tested, find the probability that the number of miles (In thousands) before it will need replacement is between 68.7 and 70.2. Round your answer to 4 decimal places. P(68.7 < z < 70.2) - d) Is the assumption that the distribution is normal necessary in order for you to answer part c? O Yes ONo

The mean number of miles (in thousands) that a car's tire will function before needing replacement is 71; the standard deviation is 11 (also in thousands). Assume a normal distribution. a) If we test 49 tires, find the probabtility that the average miles (In thousands) before need of replacement is between 68.7 and 70.2. Round your answer to 4 decimal places. P(68.7 < # < 70.2) b) Is the assumption that the distribution is normal necessary in order for you to answer part a? O Yes ONo c) If a randomly-selected individual tire is tested, find the probability that the number of miles (In thousands) before it will need replacement is between 68.7 and 70.2. Round your answer to 4 decimal places. P(68.7 < z < 70.2) - d) Is the assumption that the distribution is normal necessary in order for you to answer part c? O Yes ONo

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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The mean number of miles (in thousands) that a car's tire will function before needing replacement is 71; the standard deviation is 11 (also in thousands). Assume a normal distribution. a) If we test 49 tires, find the probability that the average miles (in thousands) before need of replacement is between 68.7 and 70.2. Round your answer to 4 decimal places. P(68.7 < z < 70.2) b) Is the assumption that the distribution ts normal necessary in order for you to answer part a? O Yes O No c) If a randomly-selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 68.7 and 70.2. Round your answer to 4 decimal places. P(68.7 < z < 70.2) - d) Is the assumption that the distribution is normal necessary in order for you to answer part c? O Yes O No
Transcribed Image Text:The mean number of miles (in thousands) that a car's tire will function before needing replacement is 71; the standard deviation is 11 (also in thousands). Assume a normal distribution. a) If we test 49 tires, find the probability that the average miles (in thousands) before need of replacement is between 68.7 and 70.2. Round your answer to 4 decimal places. P(68.7 < z < 70.2) b) Is the assumption that the distribution ts normal necessary in order for you to answer part a? O Yes O No c) If a randomly-selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 68.7 and 70.2. Round your answer to 4 decimal places. P(68.7 < z < 70.2) - d) Is the assumption that the distribution is normal necessary in order for you to answer part c? O Yes O No
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