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The mean of plant height from two rice plants (P1 and P2) and their progeny (F1 and F2) and a backcross generation (P1 x F1) are shown below.
|
Population |
Mean (in) |
|
P1 |
34.1 |
|
P2 |
65.2 |
|
F1 |
44.1 |
|
F2 |
46.2 |
|
BC1 |
39.6 |
Explain the possible reasons for the observed differences in the sample means. Account for the differences in the sample means of P1 and P2. Similarly, account for the differences in the sample means of the F1 and F2. Compare the difference in the parental generations with that in the filial generations.
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- The mean and standard deviation of plant height from two rice plants (P1 and P2) and their progeny (F1 and F2) and a backcross generation (P1 x F1) are shown below. Complete the table by calculating the variances and coefficient of variation for each population and answer the questionswhich follow (See image) 1. Explain the possible reasons for the observed differences in the sample means. Account forthe differences in the sample means of P1 and P2. Similarly, account for the differences in thesample means of the F1 and F2. Compare the difference in the parental generations with thatin the filial generations.2. Interpret the CV values from each population.3. Compare the sample variances of P1 and P2. Account for any differences. Similarly, comparethe sample variances of the F1 and F2 generations, and account for any differences. Give thepossible causes of variation in each generation.4. Calculate the broad-sense heritability of plant height in this species. Interpret your results.The mean, standard deviation, variances, and coefficient of variance of plant height from two rice plants (P1 and P2) and their progeny (F1 and F2) and a backcross generation (P1 x F1) are shown below. Explain the possible reasons for the observed differences in the sample means. Account for the differences in the sample means of P1 and P2. Similarly, account for the differences in the sample means of the F1 and F2. Compare the difference in the parental generations with that in the filial generations.A large, genetically heterogeneous group of tomato plants was usedas the original breeding stock by two different breeders, named Maryand Hector. Each breeder was given 50 seeds and began an artificialselection strategy, much like the one described in the figure. Theseeds were planted, and the breeders selected the 10 plants with thehighest mean tomato weights as the breeding stock for the next generation. This process was repeated over the course of 12 growing seasons, and the following data were obtained: Mean Weight of Tomatoes (pounds)Year Mary’s Tomatoes Hector’s Tomatoes1 0.7 0.82 0.9 0.93 1.1 1.24 1.2 1.35 1.3…
- A genetically diverse population (Population 1) of monkeyflowers is growing on an alpine slope. The seeds produced by 100 of these plants are counted and the mean and variance are calculated. The variance is 25. One plant is selected and cuttings are taken from it. These cuttings are cultivated in the greenhouse, producing many genetically identical clones of the same plant. These clones (Population 2) are then transplanted into the alpine population, allowed to grow for a year, and then the numbers of seeds produced by each of the cloned plants is counted. The variance in seed number among these cloned plants is 10. Assume that the alpine slope environment does not vary across the years of the experiment, and that there is no genotype-by-environmental variation for seed number. What is the broad-sense heritability for seed number for Population 1?The phenotypic data below are the shoot lengths of 25 F1 and 25 F2 rice plants atseedling stage, produced from the cross of IR29 and Hasawi rice varieties. The mean lengths of the shoot from IR29 and Hasawi are 23.1 cm and 46.7 cm, respectively. Tabulate and plot the frequency distributions of the F1 and F2 generations. From each distribution calculate the mean, the variance,and the standard error of the mean. What is the main difference between F1 and F2 distributions? Formulas needed:Range (R) = maximum – minimum (Use the same no. of decimal places as original data.)No. of phenotypic classes (K) = 1 + 3.3logn (Round up answer to an integer. Number may still be increased or decreased as needed.)n = total no. of valuesClass interval (CI) = R/K (Use the same no. of decimal places as original data.)The phenotypic data below are the shoot lengths of 25 F1 and 25 F2 rice plants at seedling stage, produced from the cross of IR29 and Hasawi rice varieties. The mean lengths of the shoot from IR29 and Hasawi are 23.1 cm and 46.7 cm, respectively. Tabulate and plot the frequency distributions of the F1 and F2 generations. Use the formulas below in the computations. From each distribution calculate the mean, the variance, and the standard error of the mean. Round off answers to two decimal places. What is the main difference between F1 and F2 distributions?
- Kernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of the offspring with the following genotypes: (Note: 4 contributing alleles – red; 3 contributing alleles – medium red; 2 contributing alleles – intermediate red; 1 contributing allele – red; and 0 – white (AAbb x AaBb, AABb x Aabb, aaBb x Aabb, AABb x aabb, AABb x AaBb) Show the solution through punnett square. Refer to the problem above, a wheat plant producing medium red seed is crossed with another plant producing intermediate red seed. How many individuals will be?Show the solution through punnett square. Red Medium red Intermediate red Light red WhiteHalf of the worlds population eats rice at least twice a day. Much of this rice is grown in flooded conditions, and different strains of rice are tolerant (survive) or intolerant (die) under these conditions. Rice breeders used genetic crosses to test whether tolerance to flooding is a dominant trait. Researchers used three true-breeding flood-tolerant strains, FR143, BKNFR, and Kurk, and two true-breeding flood- intolerant strains, IR42 and NB, in the crosses. Results were obtained from three sets of crosses and are reported in the Table below: Results of cross of F1 to tolerant parent: F1 plants were crossed with the tolerant parent of the cross. Number of Plants Progeny Analyzed from Intolerant Tolerant Cross Alive Dead Total 1. F2 results of cross: IR42 FR13A 187 77 264 IR42 BKNFR 192 73 265 NB Kurk 142 52 195 2. Results of cross of F1 to intolerant parent: (F1 of IR42 FR13A) IR42 14 17 31 (F1 of IR42 BKNFR) IR42 15 10 25 (F1 of NB Kurk) NB 21 35 56 3. Results of cross of F1 to tolerant parent: (F1 of IR42 FR13A) FR13A 31 0 31 (F1 of IR42 BKNFR) BKNFR 28 0 28 (F1 of NB Kurk) Kurk 40 0 40 Do the data support the hypothesis that the tolerance trait is dominant? Justify your conclusion by explaining the results from each of the three sets of crosses in terms of genotypes and phenotypic ratios. Source: T. Setter et al. 1997. Physiology and genetics of submergence tolerance in rice. Annals of Botany 79:6777.What is the relative fitness of the F1 hybrids relative to both parental populations according to this model?
- A population consists of 300 individuals with the following genotypes: AA – 100 Aa – 125 aa – 75 For the population in the problem above, imagine that the homozygous recessives are deleterious and that only 80% of these individuals survive to reproduce. If the other genotypes have a 100 % survival rate, and in each surviving individual replaces itself through reproduction, what are the values of p and q after one generation?The mean and standard deviation of plant height from two rice plants (P1 and P2) and their progeny (F1 and F2) and a backcross generation (P1 x F1) are shown below. Compare the sample variances of P1 and P2. Account for any differences. Similarly, compare the sample variances of the F1 and F2 generations, and account for any differences. Give the possible causes of variation in each generation.The mean, standard deviation, variances, and coefficient of variance of plant height from two rice plants (P1 and P2) and their progeny (F1 and F2) and a backcross generation (P1 x F1) are shown below. Calculate the broad-sense heritability of plant height in this species and interpret the results.