The number of free electrons passing through the filament of an electric lamp in one hour when the current through the filament is 0.32 A will be (1) 3×10²2 ii) 7.2×10¹⁹ (ii) 2×1026 (iv) 7.2×1021

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Q: 12/60° V 592 € j2 52 j3 92 12.12 For Practice Prob. 13.2. j692 =-449

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Q: Find GZAS(z) for the series R-L circuit shown in Figure with the inductor voltage as output. M R L V…

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Q: Write the Boolean expression equivalent to the following logic circuit. Do not simplify! A B Y D

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Q: Example: . Sketch the root locus for the following system G(s)H(s) = K (s+1) s(s+4) (s² +28+2)

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Q: 7- Determine the power factor of 220V, 0.4A, 20W fluorescent lamp? and when it will be leading or…

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Q: Solve for V2 if Ra = 24 ohms, Rb = 26 ohms and V = 24 volts. (Give the numeric value only, and use 2…

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Q: ohm per phase. Calculate the synchronizing power per mechanical degree displacement

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Q: Find i and v, in the circuit of Fig. 7.15. Let i(0) = 12 A. Answer: 12e-2¹ A, -12e-2¹ V, t > 0.

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Q: Find 11 and 12

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.