The output of the following code short int x = 15213; int iy = (int) -x; cout<<"iy=0x"<
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The output of the following code
short int x = 15213;
int iy = (int) -x;
cout<<"iy=0x"<<hex<<iy<<" == ";
Step by step
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- gien two variables a and b of type int, that have been decalred and gien values, compute their sum then assign it to another int variable,c, that has also already been declared. c++Assume that int a[ 2 ][ 2 ] = { { 1, 2 }, { 3, 4 } }; the value of a[ 1, 1 ] = ______;please code in java.. dont use very advanced coding Integer variables totalFlowers and numFlowers are read from input. A bouquet consists of numFlowers flowers, and the r of flowers is given by totalFlowers. Assign remainingFlowers with the remaining flowers after making as many bouquets possible.Ex: If the input is 13 4, then the output is:Remaining flowers: 1
- Write a code for craps game. Craps is a dice game in which the players make wagerson the outcome of the roll, or a series of rolls, of a pair of dice.The rules of the dice game craps are as follows:You roll two dice. Each die has six faces, which contain one, two, three, four, five and six spots,respectively. After the dice have come to rest, the sum of the spots on the two upward faces iscalculated. If the sum is 7 or 11 on the first throw, you win and play is over. If the sum is 2, 3or 12 on the first throw you lose and play is over. If the sum is 4, 5, 6, 8, 9 or 10 on the firstthrow, that sum becomes your “point.” To win, you must continue rolling the dice until you“make your point” (i.e., roll that same point value). You lose by rolling a 7 before making yourpoint(in python)Write a code for craps game. Craps is a dice game in which the players make wagerson the outcome of the roll, or a series of rolls, of a pair of dice.The rules of the dice game craps are as follows:You roll two dice. Each die has six faces, which contain one, two, three, four, five and six spots,respectively. After the dice have come to rest, the sum of the spots on the two upward faces iscalculated. If the sum is 7 or 11 on the first throw, you win and play is over. If the sum is 2, 3or 12 on the first throw you lose and play is over. If the sum is 4, 5, 6, 8, 9 or 10 on the firstthrow, that sum becomes your “point.” To win, you must continue rolling the dice until you“make your point” (i.e., roll that same point value). You lose by rolling a 7 before making yourpoint.Define an enumeration type triangleType that has the values scalene, isosceles, equilateral, and noTriangle.b. Write a function triangleShape that takes as parameters three numbers, each of which represents the length of a side of the triangle. The function should return the shape of the triangle. (Note: In a triangle, the sum of the lengths of any two sides is greater than the length of the third side.)c. Write a program that prompts the user to input the length of the sides of a triangle and outputs the shape of the triangle.
- The value of x at the end.int x = 1;x = x + 1;x++;What output will be produced by this code segment: for (int i = 5; i > 1; i--) { for (int j = i - 1; j > 1; j--) System.out.print (3 * j - 1); System.out.println(); }Implement the following function which takes the radius of a circle as one of its parameters and stores the circumference and area using the other two parameters.void calcCircleInfo(int radius, int *circumference, int *area)
- Declare an int constant minutesPerHour whose value is 60Define an enumeration type triangleType that has the values scalene, isosceles, equilateral, and noTriangle. Write a function triangleShape that takes as parameters three numbers, each of which represents the length of a side of the triangle. The function should return the shape of the triangle. (Note: In a triangle, the sum of the lengths of any two sides is greater than the length of the third side.) Write a program that prompts the user to input the length of the sides of a triangle and outputs the shape of the triangletrace the following code and give the output. for (int a = 1; a <= 3; a++) for (int b = 1; b <= 3; b++) cout << a+b << endl;