The paper speed of a given recording machine (say, an EKG) is 25mm/sec. This means that, at every second, 25mm of paper receive a recording (a tracing). Since paper speed is constant and distance and time are represented by a linear relationship through the origin (at time 0, no tracings have been made), we can use the rule of proportionality to calculate the time interval that corresponds to a given distance, provided that the velocity (paper speed) is constant. In other words, for a constant velocity (=d/t): d₁=d₂ t₁ t₂ 1. At a paper speed of 25mm/sec, what is the distance that corresponds to 2 seconds of recording? 2. At a paper speed of 20mm/sec, what is the time interval that in encompassed by 13mm of recorded paper? 3. What is the paper speed of an output that received 1,020 linear millimeters of recorded tracings during 17 seconds?

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The paper speed of a given recording machine (say, an EKG) is 25mm/sec. This means that, at
every second, 25mm of paper receive a recording (a tracing). Since paper speed is constant and
distance and time are represented by a linear relationship through the origin (at time 0, no
tracings have been made), we can use the rule of proportionality to calculate the time interval
that corresponds to a given distance, provided that the velocity (paper speed) is constant. In
other words, for a constant velocity (=d/t):
d₁=d₂
t₁ t₂
1. At a paper speed of 25mm/sec, what is the distance that corresponds to 2 seconds of
recording?
2. At a paper speed of 20mm/sec, what is the time interval that in encompassed by 13mm
of recorded paper?
3. What is the paper speed of an output that received 1,020 linear millimeters of recorded
tracings during 17 seconds?
4. Given the tracing below, from a machine that produced output at a constant speed of
25mm/sec, calculate the duration, in seconds, of the event marked by the interval x
x (corresponds to16.5mm)
FLIA
Transcribed Image Text:The paper speed of a given recording machine (say, an EKG) is 25mm/sec. This means that, at every second, 25mm of paper receive a recording (a tracing). Since paper speed is constant and distance and time are represented by a linear relationship through the origin (at time 0, no tracings have been made), we can use the rule of proportionality to calculate the time interval that corresponds to a given distance, provided that the velocity (paper speed) is constant. In other words, for a constant velocity (=d/t): d₁=d₂ t₁ t₂ 1. At a paper speed of 25mm/sec, what is the distance that corresponds to 2 seconds of recording? 2. At a paper speed of 20mm/sec, what is the time interval that in encompassed by 13mm of recorded paper? 3. What is the paper speed of an output that received 1,020 linear millimeters of recorded tracings during 17 seconds? 4. Given the tracing below, from a machine that produced output at a constant speed of 25mm/sec, calculate the duration, in seconds, of the event marked by the interval x x (corresponds to16.5mm) FLIA
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