The parallel plates in a capacitor have an area of 2000 cm2 (2.00 x 10-1 m2 ) and area 1.00 cm (1.00 x10-2 m) apart. The original potential difference Vo between the plates is 3600 V and it decreases to 1000 V when a sheet of a dielectric is inserted between the plates. Find (a) the original capacitance Co of the capacitor (b) the magnitude of the charge, Q, in each plate? (c) the capacitance, C, after the dielectric is inserted
Dielectric Constant Of Water
Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.
Electrostatic Potential and Capacitance
An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
1. The parallel plates in a capacitor have an area of 2000 cm2 (2.00 x 10-1 m2 ) and area 1.00 cm (1.00 x10-2 m) apart. The original potential difference Vo between the plates is 3600 V and it decreases to 1000 V when a sheet of a dielectric is inserted between the plates.
Find
(a) the original capacitance Co of the capacitor
(b) the magnitude of the charge, Q, in each plate?
(c) the capacitance, C, after the dielectric is inserted
(d) the dielectric constant of the dielectric
(e) the permittivity ε of the dielectric
(f) the original electric field, Eo , between the plates
(g) the electric field, E , afte
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
