The Pear company sells pPhones. The cost to manufacture x pPhones is C(x) = – 24x2 + 66000x + 18296 dollars (this includes overhead costs and production costs for each pPhone). If the company sells x pPhones for the maximum price they can fetch, the revenue function will be R(x) = - 31a + 206000x dollars. How many pPhones should the Pear company produce and sell to maximimze profit? (Remember that profit=revenue-cost.)

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.1: Quadratic Functions
Problem 6SC: A company that makes and sells baseball caps has found that the total monthly cost C in dollars of...
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The Pear company sells pPhones. The cost to manufacture xx pPhones is C(x)=−24x2+66000x+18296C (this includes overhead costs and production costs for each pPhone). If the company sells x pPhones for the maximum price they can fetch, the revenue function will be R(x)=−31x2+206000x dollars.

How many pPhones should the Pear company produce and sell to maximimze profit? (Remember that profit=revenue-cost.) 

= – 24x² + 66000x + 18296
The Pear company sells pPhones. The cost to manufacture x pPhones is C(x)
dollars (this includes overhead costs and production costs for each pPhone). If the company sells x pPhones for
the maximum price they can fetch, the revenue function will be R(x) = - 31a² + 206000x dollars.
%3D
%3D
How many pPhones should the Pear company produce and sell to maximimze profit? (Remember that
profit=revenue-cost.)
Transcribed Image Text:= – 24x² + 66000x + 18296 The Pear company sells pPhones. The cost to manufacture x pPhones is C(x) dollars (this includes overhead costs and production costs for each pPhone). If the company sells x pPhones for the maximum price they can fetch, the revenue function will be R(x) = - 31a² + 206000x dollars. %3D %3D How many pPhones should the Pear company produce and sell to maximimze profit? (Remember that profit=revenue-cost.)
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