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The perimeter of a rectangle is 38 meters and the length is 3 meters longer than the width. Find the dimensions of the rectangle. Let x ength and y = the width. The corresponding modeling system is S 2x + 2y = 38 .Use the method of substitution to solve this system. X – y = 3 Answer 2 Points Keybo Length of the rectangle = m, Width of the rectangle =

The perimeter of a rectangle is 38 meters and the length is 3 meters longer than the width. Find the dimensions of the rectangle. Let x ength and y = the width. The corresponding modeling system is S 2x + 2y = 38 .Use the method of substitution to solve this system. X – y = 3 Answer 2 Points Keybo Length of the rectangle = m, Width of the rectangle =

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter7: Conic Sections And Quadratic Systems
Section7.4: Solving Nonlinear Systems Of Equations
Problem 61E
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The perimeter of a rectangle is 38 meters and the length is 3 meters longer than the width. Find the dimensions of the rectangle. Let x = the length and y = the width. 2x + 2y = 38 Use the method of substitution to solve this system. 3D3 The corresponding modeling system is X – y Answer 2 Points E Keyp Keyboard Short Length of the rectangle = m, Width of the rectangle = 21 Hawkes Learning e to search DELL
Transcribed Image Text:The perimeter of a rectangle is 38 meters and the length is 3 meters longer than the width. Find the dimensions of the rectangle. Let x = the length and y = the width. 2x + 2y = 38 Use the method of substitution to solve this system. 3D3 The corresponding modeling system is X – y Answer 2 Points E Keyp Keyboard Short Length of the rectangle = m, Width of the rectangle = 21 Hawkes Learning e to search DELL
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