The points at which the graph of the equation 8x2+ y² – 16x + 8y + 8=0 has horizontal tangent lines are: A (1,0) and (1, - 8) ® (-4, 1+ V7) and (-8, 1- 7) (0,1) and (-8, 1) (1+ Vz. -4) and ( 1 – VZ.-8) E none of the given choices

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.2: Introduction To Conics: parabolas
Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
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The points at which the graph of the equation 8x²+ y2 – 16x + 8y + 8=0 has
horizontal tangent lines are:
A
(1,0) and (1, – 8)
(-4, 1+ 7) and (-8, 1– V2)
(c)
(0,1) and (-8, 1)
D (1+ V7, - 4) and (1 – V7. - 8)
E none of the given choices
B.
Transcribed Image Text:The points at which the graph of the equation 8x²+ y2 – 16x + 8y + 8=0 has horizontal tangent lines are: A (1,0) and (1, – 8) (-4, 1+ 7) and (-8, 1– V2) (c) (0,1) and (-8, 1) D (1+ V7, - 4) and (1 – V7. - 8) E none of the given choices B.
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