The population of bears in a national forest is changing according to the function N(t) = 850(0.96)', where t is the time in years and N() is the number of bears. Which statement explains how the bearpopulation is changing?A.O The population is decreasing by 4% per year.B.The population is increasing by 96% per year.c.O The population is decreasing by 96% per year.D.O The population is increasing by 4% per year.

The population of bears in a national forest is changing according to the function N(t) = 850(0.96)', where t is the time in years and N() is the number of bears. Which statement explains how the bBeal population is changing? A. The population is decreasing by 4% per year. B.O The population is increasing by 96% per year. c.O The population is decreasing by 96% per year. D. The population is increasing by 4% per year.

The population of bears in a national forest is changing according to the function N(t) = 850(0.96)', where t is the time in years and N() is the number of bears. Which statement explains how the bBeal population is changing? A. The population is decreasing by 4% per year. B.O The population is increasing by 96% per year. c.O The population is decreasing by 96% per year. D. The population is increasing by 4% per year.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter7: Exponents And Exponential Functions

Section7.8: Transforming Exponential Expressions

Problem 15PFA

See similar textbooks

Similar questions

Repeat the previous exercise to find the formula forthe APY of an account that compounds daily. Usethe results from this and the previous exercise todevelop a function I(n)for the APY of any accountthat compounds n times per year.
When a certain drug is taken orally, the concentration of the drug in the patient's bloodstream After t minutes is given by C(t)=0.06t0.0002t2 where 0t240 and concentration is measured in mg/L .When is the maximum serum concentration reached, and what is that maximum concentration?
Decay of Litter Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be the amount of litter present, in grams per square meter, as a function of time t in years. If the litter falls at a constant rate of L grams per square meter per year, and if it decays at a constant proportional rate of k per year, then the limiting value of A is R=L/k. For this exercise and the next, we suppose that at time t=0, the forest floor is clear of litter. a. If D is the difference between the limiting value and A, so that D=RA, then D is an exponential function of time. Find the initial value of D in terms of R. b. The yearly decay factor for D is ek. Find a formula for D in term of R and k. Reminder:(ab)c=abc. c. Explain why A=RRekt.
What is the composition of two functions, fg ?
Near the surface of the moon, the distance that an object falls is a function of time. It is given by d(t)=2.6667t2 , where t is in seconds and d(t) is in feet. If an object is dropped from a certain height, find the average velocity of die object from t=1tot=2 .
bThe average rate of change of the linear function f(x)=3x+5 between any two points is ________.
Suppose that the initial mass of radioactive substance is m0 and the half-life of the substance is h. Let m(t) be the mass remaining at time t. a What is meant by the half-life h? b Write a formula for m(t) in terms of the half-life h. c Write a formula for the relative decay rate r in terms of the half-life h. d Write a formula for m(t) in terms of the relative decay rate r.