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- The 5-kg ball A revolves at a constant speed ? in a horizontal circle as shown in Figure Q2. If ? = 50° and ? = 7.9m. Explain how r and the mass of the ball should be adjusted if the speed of the ball is to be increased.The velocity of a particle is v = { 3i + (6 - 2t)j} m/s where t is in seconds. If r = 0 when t = 0, determine the magnitude of the displacement In meters of the particle during the time interval t = 1 s to t = 3 s.The position of a particle is described by r = (t3 + 4t − 4) mm and θ = (t3/2) rad, where t is in seconds. Determine the magnitudes of the particle’s velocity in m/s at the instant t = 2s.
- Situation 2: The displacement (in meter) of a particle moving along x - axis is givenby x=At^2 + B , where A = 2m and B = 3m. Calculate average velocity between t =3sand t = 5s.Situation 2: Calculate instantaneous velocity at t = 5sSituation 2: Calculate instantaneous acceleration.1.The position of a particular particle as a function of is given by r=(8.5t i+5.6j-2t 2k )m (a) Determine the particle’s velocity and acceleration as a function of time. (b) Find the instantaneous velocity and acceleration of the particle at t=3.0 s. Question 2 . At t=0, a particle starts from rest and moves in the xy space with an acceleration a=(4 i+6 2 j)m/s . Determine (a) the velocity and position of the particle as a function of time. (b) evaluate the speed and position of the particle at t=5.0 s.The position coordinate of a particle which is confined to move along a straight line is given by s = 2t³ - 24t + 6, where s is measured in meters from a convenient origin and t is in seconds. Determine (a) the time required for the particle to reach a velocity of 72 m/s from its initial condition at t = 0
- The motion of a particle is defined by the parametric equations ax =0.8t, ay =2–0.3t, az =5 where “a” is in m/s2 and t in seconds.The particle is at rest and is placed at the origin at t = 0. What is the acceleration of the particle after 10 seconds? What is the velocity of the particle after 10 seconds?1. - the velocity of particle at t = 9 seconds: a. 122 b. 747 c. 167 d. none e. 898 - the acceleration of the particle at t = 9 seconds: a.none b. 42 c. 46 d. 44 e. 48 - the total displacement after 6 seconds: a. -78 b. 100 c. 78 d. 102 e. none - the average speed from t = 0 to t = 6 seconds: a. 20 b. 17 c. -17 d. none e. -13 - the average velocity from t = 0 to t = 6 seconds: a. 20 b. none c. -13 d. 17 e. 13Determine the magnitude of velocity of the ball (m/s) when t = 1.45 seconds.
- Find the following using the photo below. e. If a = 2 m/s2, determine v at s = 4 m if v = 3 m/s at s = 0.f. If a = 4 m/s2, determine s when t = 3 s if v = 2 m/s and s = 2 m when t = 0.g. When t = 0 the particle is at A. In four seconds it travels to B, then in another six seconds it travels to C. Determine the average velocity and the average speed. The origin of the coordinate is at O.The velocity of a particle moving along the x-axis is given by the function v (t) = 2t^3 + 15 for t > 0. Find the total distance traveled by the particle from t=2 to t=4.Fluid Mechanics question: A device used for measuring the specific weight of a liquid consists of a u-tube manometer as shown. The manometer tube has an internal diameter of 0.5 cm and originally has water in it. Exactly 2 cm3 of unknown liquid is poured into one leg of the manometer, and a displacement of 5cm is measured between the surfaces as shown. What is the specific weight of the unknown liquid?