The position of a projectile launched from the origin at t=0 is given by 7 = (40iOf + 50j)m at t = 2s. If the projectilewas launched at an angle 0 from the horizontal, then 0 is(take g= 10 ms2)(а) tan'-1(b) tan(c) tan-17(d) tan3/2415n2/37/t

Name: The position of a projectile launched from the origin at t=0 is given
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Description: The position of a projectile launched from the origin at t=0 is given by 7 = (40iOf + 50j)m at t = 2s. If the projectilewas launched at an angle 0 from the horizontal, then 0 is(take g= 10 ms2)(а) tan'-1(b) tan(c) tan-17(d) tan3/2415n2/37/t

Initial position of projectile = 0i^ + 0j^Position of projectile after 2 seconds = 40i^ + 50j^ m g =…

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The position of a projectile launched from the origin at t= O is given by = (40î + 50})m at t = 2s. If the projectile %3D was launched at an angle 0 from the horizontal, then 0 is (take g= 10 ms 2) -1 (a) tan 3 -13 (b) tan (c) tan 4 (d) tan 3/2415

The position of a projectile launched from the origin at t= O is given by = (40î + 50})m at t = 2s. If the projectile %3D was launched at an angle 0 from the horizontal, then 0 is (take g= 10 ms 2) -1 (a) tan 3 -13 (b) tan (c) tan 4 (d) tan 3/2415

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 9P

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