The positions of two blocks at successive 0.20-second time intervals are represented by the numbered squares in the figure below. The blocks are moving toward the right. The accelerations of the blocks are related as follows: The acceleration of "a" is greater than the acceleration of "b". The acceleration of "a" equals the acceleration of "b". Both accelerations are greater than zero. The acceleration of "b" is greater than the acceleration of "a". The acceleration of "a" equals the acceleration of "b". Both accelerations are zero. Not enough information is given to answer the question.
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
The positions of two blocks at successive 0.20-second time intervals are represented by the numbered squares in the figure below. The blocks are moving toward the right.
The accelerations of the blocks are related as follows:
- The acceleration of "a" is greater than the acceleration of "b".
- The acceleration of "a" equals the acceleration of "b". Both accelerations are greater than zero.
- The acceleration of "b" is greater than the acceleration of "a".
- The acceleration of "a" equals the acceleration of "b". Both accelerations are zero.
- Not enough information is given to answer the question.
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