The program follows to use a shared binary semaphore T.   Process A   int Y;             A1: Y = X*2;       A2: X = Y;         signal(T);           Process B int Z; B1: wait(T); B2: Z = X+1; X = Z; T is set to 0 before either process begins execution and, as before, X is set to 5. Now, how many different values of X are possible after both processes finish executing? a) one b) two c) three d) four

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