An engineer must choose between two technically equivalent alternatives, A and B. Based upon the data in the table below over the 12year analysis periodand an interest rate of 9%, the PW of machine A is:ABFirst Cost$3,000$6,000Annual Maintenance$500$300End of Useful LifeSalvage Value$700$1,000Useful Life5 years|15 уearsO PWA=-3000-3000(P/F,9%,5)-3000(P/F,9%,10)-500(P/A,9%,15)+700(P/F,9%,5)+700(P/F,9%,10)+700(P/F,9%,15)O PWA=-3000-3000(P/F,9%,10)-500(P/A,9%,15)+700(P/F,9%,5)+700(P/F,9%,10)+700(P/F,9%,15)O PWA=-3000-3000(P/F,9%,5)-3000(P/F,9%,10)-500(P/F,9%,15)+700(P/F,9%,5)+700(P/F,9%,10)+700(P/F,9%,15)O PWA=-3000-3000(P/F,9%,5)-3000(P/F,9%,10)-500(P/A,9%,10)+700(P/F,9%,5)+700(P/F,9%,10)+ 700(P/F,9%,15)

Answered: the PW of machine A is:

Business

Accounting

the PW of machine A is:

EBK CONTEMPORARY FINANCIAL MANAGEMENT

14th Edition

ISBN:9781337514835

Author:MOYER

Publisher:MOYER

Chapter10: Capital Budgeting: Decision Criteria And Real Option

Section10.A: Mutually Exclusive Investments Having Unequal Lives

Problem 2P

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