The ratio of direct stress to the limit. The ratio is known as Volumetric strain O Bulk modulus O Shear modulus O Modulus of elasticity Poisson's ratio
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- Question- Principal stress at a point in an elastic material are 1.50 (tensile), o (tensile) and 0.50 (compressive). The elastic limit in tension is 210 MPa and poisson's ratio=0.3. Find the value of o at the failure when computed by the maximum principal strain theory.Which of the following best represents the distribution of the normal stress on the cross section of a linearly elastic member subjected to flexural loading? A.Uniform B.Parabolic C.Cubic D.Linear How does the flexural STRAIN on a fiber vary with respect to its distance from the neutral axis within elastic loading? A.Uniformly (it remains the same) B.Linearly decreases C.Exponentially increases D.Linearly increases Which of the following expressions best approximates the flexural bending stress at the neutral axis of a flexurally-loaded member with a rectangular cross section of depth 300mm, area 0.18m^2, and internal bending moment 2kN-m? a.0 MPa b.0.22 MPa c.0.44 MPa d.0.11 MPa Which of the following expressions is the maximum flexural bending stress of an L-meter beam with a constant rectangular cross section of width b and depth h subjected to uniform load Wo? Select one: OA 3 w L² 8 Ah о в. 3w,L² Ah O C. 3 w L² 2 Ah OD. 3 w L² 4 AhPart B - The internal reaction at B Assume that the axial member is in equilibrium and the applied forces are an unknown load F₁. F = 5 kN. F₂ = 3 kN, and F₁ = 2 kN. Calculate the internal resultant normal force at section B. Express your answers to three significant figures in kN. ▸ View Available Hint(s) PB = Submit ΨΕ ΑΣΦΠ Part C - The internal reaction at D PD = Submit D] ΑΣΦΩΤ vec Assume that the axial member is in equilibrium and the applied forces are an unknown load F₁, F₂=5 kN. F₂ = 3 kN. and F₁ = 2 kN. Calculate the internal resultant normal force at section D. Express your answers to three significant figures in kN. ▸ View Available Hint(s) Part D - The average normal stress µA vec Value P * ? ? Units KN 2 ? Suppose the axial member has a circular cross section with a diameter of d = 16 cm at section B and a diameter of dp = 8 cm at section D. What is the average normal stress in the section with the maximum magnitude stress? Express your answer to three significant figures…
- The components of plane stress at a critical point on a steel shell are shown in the figure below. The yield stress (Gy) of the material in simple tension is 250 MPa. 60 MPa 40 MPa 70 MPa (a) Determine the magnitude of the principal stresses and maximum shear stress. Sketch these on appropriately orientated elements. (b) Calculate the factor of safety against yield on the basis of i. Tresca failure criterion ii. Von Mises failure criterionQ- Principal stress at a point in an elastic material are 1.5 o (tensile), o (tensile) and 0.5o (compressive). The elastic limit in tension is 210 MPa and μ = 0.3. Find the value of o at failure when computed by maximum principal strain theory.At a point in a piece of elastic material there are three mutually perpendicular planes on which the stresses are are follows: tensile stress 50 N/mm2 and shear stress 40 N/mm2 on one plane, compressive stress 35 N/mm² and complementary shear stress on the third plane. Find : (a) the principal stresses and the positions of the planes on which they act, (b) the positions of the planes on which there is no normal stress.
- Material is subjected to a general state of plane stress. Express the strain energy density in terms of the elastic constants E, G, and n and the stress components sex, sy, and txy.Which of the following is NOT TRUE in the elastic analysis of circular members under torsion? O Torsional shear stress varies linearly with the radial distance from the axis of the shaft. O Torsional shear stress is minimum at a point on the surface of the circular shaft. O Torsional shear stress is zero at the center. O Torsional stress is maximum when the distance from the center is equal to the radius.Steel Stress-Strain diagram. Which of the following statements is NOT correct? Engineering stress is the stress computed using the original area and not the necking down area. The constant stress region is called the yield plateau or plastic range. The linear portion is also called the plastic range. The proportional limit, elastic limit, upper and lower yield points are very close to one another and are treated as a single point called the yield point.
- A plane element is subjected to the stresses as shown. Determine a) the principal stresses and their directions b) the maximum and minimum shearing stresses c) Sketch the Mohr's Circle for this plane stresses 30 MPa |90 MPa 40 MPaQ: A piece of material is subjected to tensile stress of 70 N/mm² in one direction and a compressive stress of 50 N/mm² in a direction at right angles to the previous one. Find fully the stresses on a plane the normal of which makes an angle of 40 degree with the 70 N/mm2 stress.Direct stresses of 120 N/mm2 (tension) and 90 N/mm2 (compression) are applied at a particular point in an elastic material on two mutually perpendicular planes. The principal stress in the material is limited to 200 N/mm2 (tension). Calculate the allowable value of shear stress at the point on the given planes. Determine also the value of the other principal stress and the maximum value of shear stress at the point using Mohr’s Circle.