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The Reg for the H₂O + H₂O → Kw [H3O+¹][OH-¹] tion of water with Wal is called Zw H3O+1 + OH-1 [H₂O]² The inverse logarithm, or -log, of [H3O+¹][OH-¹] = 10-14 is pH + pOH = 14 1. What happens to the [H3O+¹] when base is added to neutral water? the [H3O+¹] goes [H3O+¹][OH-¹] (1 x 10-7)² = 1 x 10-14 2. What happens to the pH when base is added to neutral water? an example of a decreased [H3O+¹] is [H3O+¹] = 1 x 10-8. Thus pH = -log[108] = 8 thus, adding acid makes the pH go 3. What happens to the [H3O+1] when base is added to neutral water? in the equation [H3O+¹][OH-¹] = 10-14, when [OH-¹] increases, the [H3O+¹] goes 4. What happens to the pOH when base is added to neutral water? when [OH-¹] increases, the pOH goes a. down this can also be seen using pH + pOH = 14 5. What happens to the Kw when base is added to neutral water? because it's a constant. b. up c. no change since the pOH = -log[OH-¹]

The Reg for the H₂O + H₂O → Kw [H3O+¹][OH-¹] tion of water with Wal is called Zw H3O+1 + OH-1 [H₂O]² The inverse logarithm, or -log, of [H3O+¹][OH-¹] = 10-14 is pH + pOH = 14 1. What happens to the [H3O+¹] when base is added to neutral water? the [H3O+¹] goes [H3O+¹][OH-¹] (1 x 10-7)² = 1 x 10-14 2. What happens to the pH when base is added to neutral water? an example of a decreased [H3O+¹] is [H3O+¹] = 1 x 10-8. Thus pH = -log[108] = 8 thus, adding acid makes the pH go 3. What happens to the [H3O+1] when base is added to neutral water? in the equation [H3O+¹][OH-¹] = 10-14, when [OH-¹] increases, the [H3O+¹] goes 4. What happens to the pOH when base is added to neutral water? when [OH-¹] increases, the pOH goes a. down this can also be seen using pH + pOH = 14 5. What happens to the Kw when base is added to neutral water? because it's a constant. b. up c. no change since the pOH = -log[OH-¹]

Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter8: Acids And Bases
Section: Chapter Questions
Problem 8.117P
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The Keg for the reaction of water with water is called Kw H₂O + H₂O → H3O+1 + OH-¹ [H3O+¹][OH-¹] Kw = = [H₂O]² The inverse logarithm, or -log, of [H3O+¹][OH^¹] = 10-¹4 is pH + pOH = 14 1. What happens to the [H3O+¹] when base is added to neutral water? the [H3O+¹] goes [H3O+¹][OH-¹] = (1 x 10-7)² = 1 x 10-14 2. What happens to the pH when base is added to neutral water? an example of a decreased [H3O+1] is [H3O+¹] = 1 × 10-8. Thus pH = -log[108] = 8 a. down thus, adding acid makes the pH go 3. What happens to the [H3O+¹] when base is added to neutral water? in the equation [H3O+¹][OH¯¹] = 10-14, when [OH-¹] increases, the [H3O+¹] goes 4. What happens to the pOH when base is added to neutral water? when [OH-¹] increases, the pOH goes this can also be seen using pH + pOH = 14 5. What happens to the Kw when base is added to neutral water? because it's a constant. b. up c. no change since the pOH = -log[OH-¹]
Transcribed Image Text:The Keg for the reaction of water with water is called Kw H₂O + H₂O → H3O+1 + OH-¹ [H3O+¹][OH-¹] Kw = = [H₂O]² The inverse logarithm, or -log, of [H3O+¹][OH^¹] = 10-¹4 is pH + pOH = 14 1. What happens to the [H3O+¹] when base is added to neutral water? the [H3O+¹] goes [H3O+¹][OH-¹] = (1 x 10-7)² = 1 x 10-14 2. What happens to the pH when base is added to neutral water? an example of a decreased [H3O+1] is [H3O+¹] = 1 × 10-8. Thus pH = -log[108] = 8 a. down thus, adding acid makes the pH go 3. What happens to the [H3O+¹] when base is added to neutral water? in the equation [H3O+¹][OH¯¹] = 10-14, when [OH-¹] increases, the [H3O+¹] goes 4. What happens to the pOH when base is added to neutral water? when [OH-¹] increases, the pOH goes this can also be seen using pH + pOH = 14 5. What happens to the Kw when base is added to neutral water? because it's a constant. b. up c. no change since the pOH = -log[OH-¹]
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