The remove method of the reference-based list implementation requires O(N) time since it needs to relocate members following the removal operation. Is it true or false?
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- Because it needs to relocate members after the removal operation, the remove method of the reference-based list implementation takes O(N) time. True or falseFor an array Based Implementation of Lists with Dynamic Allocation, why we should define a destructor by ourselves and what the destructor will do?Write the code to delete a node in the middle of a list implemented as a linked list with the dummy node (see Exercise 3). Compare your answer with the answer to Exercise 3. Are they the same? What do you conclude? Does the dummy node simplify the operation on the list? How?
- Why is a circular array implementation not as attractive as an implementation for a list as it was for a queue?Please explai The list ADT interface and its implementation remove the need for the original list interface and its two implementing classes (ElementNode & EmptyNode). Group of answer choices A. True B. False C. No answer text provided. D. No answer text provided. Q#2, What is the type of the argument to a sort operation on a list? Group of answer choices A. Function B. Predicate C. Comparator D. BiFunctionwrite a code in modules and also with main class to implement the operation on linked list.. (searching , traversing , updating , and inserting.) insertion will be In empty list, In front of list, In the middle of list, at the end of list. The code should be in java language and also with simple coding and explanation.
- The for construct is a recursive procedure that operates on a given list. Thus, it works so long as there are objects to process. Is this a genuine or untrue claim?Is it possible to implement a sorted linked list with a DLL? What advantage a DLL implementation may have over a singly linked list? Use a specific example or application to support your argument.Turn the linked list implementation into a circular list: Have the previous pointer of the first node point to the last node, and the next pointer of the last node point to the first node. Then remove the last pointer in the List class because the value can now be obtained as first->previous. Reimplement the member functions so that they have the same effect as before. c++ please use linked lists.
- Turn the linked list implementation into a circular list: Have the previous pointer of the first node point to the last node, and the next pointer of the last node point to the first node. Then remove the last pointer in the List class because the value can now be obtained as first->previous. Reimplement the member functions so that they have the same effect as before. c++Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list def show_ids(M, level=0): k = M.first_node while k is not None: print(" "*2*level, id(k)) if (str(k.value.__class__.__name__) == str(M.__class__.__name__)): show_ids(k.value, level+1) k = k.next W=L2(Node(10, Node(L2(Node(14, Node(15, Node(L2(Node(16, Node(17))))))), Node(20, Node(30)))) )show_ids(W) Develop your solution as follows: - First copy the nodes of the current list (self) - Create a new list with the copied nodes - Loop through the nodes of the new list checking the value field - If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L):…help with this function C++ Write a recursive method, to be included in an unsorted linked list class, called greater, that will receive an x parameter. The method will print the info of nodes that contain a value that is greater than theparameter.