The research team of a sophisticated and well-known hospital in the country is studying the occurrence of strength threat elements when patients recovered from the coronavirus disease 2019, represented by R, W and C. The probability that a randomly selected patient has only one of those three elements and clearly do not have the others is 0.1. The probability that a randomly selected patient has two out of three elements is 0.15. And the probability that a patient has all these threat elements is 1/4, given that he has elements R and W. Then the probability that the patient selected has none of the strength threat elements given that he does not have element R is m/n, where m and n are relatively prime positive integers. Find m-n.
The research team of a sophisticated and well-known hospital in the country is studying the occurrence of strength threat elements when patients recovered from the coronavirus disease 2019, represented by R, W and C. The probability that a randomly selected patient has only one of those three elements and clearly do not have the others is 0.1. The probability that a randomly selected patient has two out of three elements is 0.15. And the probability that a patient has all these threat elements is 1/4, given that he has elements R and W. Then the probability that the patient selected has none of the strength threat elements given that he does not have element R is m/n, where m and n are relatively prime positive integers. Find m-n.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 32E
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The research team of a sophisticated and well-known hospital in the country is studying the occurrence of strength threat elements when patients recovered from the coronavirus disease 2019, represented by R, W and C. The probability that a randomly selected patient has only one of those three elements and clearly do not have the others is 0.1. The probability that a randomly selected patient has two out of three elements is 0.15. And the probability that a patient has all these threat elements is 1/4, given that he has elements R and W. Then the probability that the patient selected has none of the strength threat elements given that he does not have element R is m/n, where m and n are relatively prime positive integers. Find m-n.
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