Solution: Kso=1.41-10-11 The resistance of a saturated solution of PbSO4 (very insoluble salt) at 291K is of 1.7x106 0, being the resistivity of pure water 7.1x105 Ocm. 1. Determine the solubility product of PBSO4 at 291K knowing that Am° (SO4 2)=136 0-1cm?mol 1 and Am° (Pb+2)=122 o-lcm?mol1. 2. How many centimeters will the ion move Pb+2 in one second when applying a potential difference of 25V between two electrodes 1 cm apart?

Fundamentals Of Analytical Chemistry
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Author:Skoog
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Chapter34: Miscellaneous Separation Methods
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Solution: Kso=1.41-10-11
The resistance of a saturated solution of
PbSO4 (very insoluble salt) at 291K is of
1.7x106 0, being the resistivity of pure
water 7.1x105 Ocm.
1. Determine the solubility product of
PBSO4 at 291K knowing that Am° (SO4
2)=136 0lcm?mol-1 and Am° (Pb+2)=122
o-lcm?mol-1,
2. How many centimeters will the ion move
Pb+2 in one second when applying a
potential difference of 25V between two
electrodes 1 cm apart?
Transcribed Image Text:Solution: Kso=1.41-10-11 The resistance of a saturated solution of PbSO4 (very insoluble salt) at 291K is of 1.7x106 0, being the resistivity of pure water 7.1x105 Ocm. 1. Determine the solubility product of PBSO4 at 291K knowing that Am° (SO4 2)=136 0lcm?mol-1 and Am° (Pb+2)=122 o-lcm?mol-1, 2. How many centimeters will the ion move Pb+2 in one second when applying a potential difference of 25V between two electrodes 1 cm apart?
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