The result of the logic gate is O A BC+AB+AB O AB+AC +ABC O AC+ABC+AB O BC+AB+ABC Skip
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- Design a combinational logic circuit that takes a 3–bit input and has one output P. The P output should be active high only when the inputs corresponds to a prime number Note: the prime numbers: Prime numbers are 2, 3, 5, 7… Select one: a. P= AC+B b. P= A'C+A'B c. P= AC+A'B d. P= AC+A'B'The output of the logic circuit is ... A exnor B A or B A and B A exor B None of thisA 1bit 4 to 1 multiplexer, the 4 inputs of the multiplexer will be the output of another combinational circuit with A and B as an input:00 = 1bit Adder01 = 1bit Subtractor10 = 1bit Comparator (equals)11 = XOR • truth table• Boolean Expression• Logic Circuit Here is the truth table guide:
- a. Draw a circuit which produces Sum and CarryOut from inputs A and B (this circuit is known as a half adder). You should use exactly one AND gate and one XOR (exclusive or) gate. b. Give the truth table for a full adder (which incorporates a carry-in bit to the sum of A and B):If a two-input logic gate produces an output of logic HIGH, only if both inputs are different, then the logic gate IC isIC 7432O IC 7486IC 7400IC 7408Design a synchronous sequential logic circuit that counts through the repetitive binary sequence 101, 111, 010, 100, 000, 001, 011, 101, etc. Implement your design using the JK- flip flops and a minimum number of logic gates
- A combinational circuit is defined by the following three Boolean functions. Design the circuit with a decoder and external gates. F1 = x' y' z' + xzF2 = x y' z' + x'yF3 = x' y' z + xyImplement the following Boolean expression with exclusive- OR and AND gates: F=AB′CD′+A′BC D′+AB′C′D+A′BC′DGiven a 4-bit signed integer, design a circuit that outputs its absolute value. You can assume that the input will always have a valid output. (a) Draw a logic diagram of this circuit. You may use 4-bit half adder(s), 2x1 4-bit multiplexer(s), and any logic gate(s) in your design. (b) With the following Verilog code, implement your design above in Verilog. module half_adder (input [3:0] a, input [3:0] b, output [3:0] s); assign s = a + b; endmodule module mux(input [3:0] D0, input [3:0] D1, input S, output reg [3:0] O); always @(*) begin if (S == 0) O = D0; else if (S == 1) O = D1; else O = 4’bx; end endmodule