The resultant loading force is 2.5 kN/m A O 09 O 5 07 3 m kN. 0.5 kN/m B 1.5 kN -1 m-
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- If a tire has a contact patch length of 104 mm, and is braking at 0.08 slip longitudinally across a road surface, what is the combined longitudinal length of slip and shear in the contact patch? Express your answer in mm to one decimal place.Which of the following has the dimension for density. M1 L1 T-2 M-1 L1 T 2 M1L-3 M L -1 T-2Determine the shear force acting at each of the following locations:(a) x = 0+ ft (i.e., just to the right of support A)(b) x = 9 ft(c) x = 12.333333333333 ftWhen entering your answers, use the shear force sign convention.Answer:(a) V = kips.(b) V = kips.(c) V = kips. The shear-force diagram crosses the V = 0 axis between points A and B. Determine the location x where V = 0 kips.Answer: x = Enter your answer in accordance to the question statement ft. Determine the maximum bending moment that acts anywhere in the beam. When entering your answer, use the bending moment sign convention.Answer: Mmax = Enter your answer in accordance to the question statement kip-ft. Use the graphical method to determine the bending moment acting at each of the following locations:(a) x = 3.3 ft(b) x = 9 ft(c) x = 12.6 ftWhen entering your answers, use the bending moment sign convention.Answers:(a) M = kip-ft.(b) M = kip-ft.(c) M = kip-ft.
- Q1 / B : 1. Convert the moment of 500 Ib.S to SI units *The 50 N force is applied to the lever cutter handle. Determine the force exerted by the cutting blade in part E. Dimensions in mm.Determine the shear stress of the cylinder pivot pin (φ25mm). The clamping force of the pliers is 6000N. The dimensions of the structure are: X1 = 10 mm X2 = 120 mm Y1 = 110 mm Y2 = 798 mm Use the units [N, mm], ie the answer comes in MPa !!! Please enter a numeric value only !!