The results of a standard Proctor test are given below. Determine the maximum dry unit weight of compaction and the optimum moisture content. Volume of Proctor mold (ft³) 1/30 1/30 1/30 1/30 1/30 Weight of wet soil in the mold (lb) 3.26 4.15 4.67 4.02 3.63 Moisture content (%) 8.4 10.2 12.3 14.6 16.8

The results of a standard Proctor test are given below. Determine the maximum dry unit weight of compaction and the optimum moisture content. Volume of Proctor mold (ft³) 1/30 1/30 1/30 1/30 1/30 Weight of wet soil in the mold (lb) 3.26 4.15 4.67 4.02 3.63 Moisture content (%) 8.4 10.2 12.3 14.6 16.8

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter5: Soil Compaction

Section: Chapter Questions

Problem 5.15P

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2. The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in mold Moisture (cu.m) (kg) (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture content
The following data was obtained from standard proctor compaction test: Weight of Weight of mold+ Weight of mold+ base compacted moist plate, w1, (g Moist Moisture Dry unit unit Test No. moist content, weight, soil+ base plate, compacted weight, W2, (g) We(%) soil, (g/cm3) Ymoist (g/cm3) W2-W1, (g) 1 15780 20700 15780 21160 3 15780 21300 15780 21360 15780 21400 Water content determination: wi(mass of empty can) W2(mass of can+ moist soil) W3(mass of can+ dry soil) Test No. Water content (W%) 1. 15.34 73.18 71.06 2. 15.34 84.45 80.52 3 12.66 59.58 56.64 4 16.84 88.91 83.61 12.66 98.1 90.33 Volume of mold = 944cm3 Calculate the maximum dry unit weight and O.M.C (show all your calculations and drawing)
A 627-g sample of sand was found to have the following amounts of material retained on each sieve/pan: 3/8 in. = 22 g, No. 4 = 45 g, No. 8 = 96 g, No. 16 = 122 g, No. 30 = 163 g. No. 50 86 g, No. 100 = 51 g, No. 200 = 30 g, pan = 11 g a. Calculate the fineness modulus of the sand. b. Is this sieve analysis valid for acceptance purposes? Explain why. c. Does the sand meet the particle size criteria of ASTM C 33. Fully justify your answer (list and check all relevant criteria from ASTM C33)
A compaction test was conducted and standard Proctor compaction procedure was used. The weight of a compacted soil specimen plus mold was determined to be 3815g. The volume and weight of the mold were 1/30 ft3 and 2050g, respectively. The water content of the specimen was 9.1%. Compute both the wet and dry unit weights of the compacted specimen. Answers in lb/ft3.
3. Given below the tabulated result in the field of compaction test. A. Unit Weight Determination 1 2 3 4 Test Number Wt. of Mold + Compaction Soil 5.9 kg 6.2 kg 6.3 kg 6.1 kg 6.0 kg 4.2kg 4.2 kg 4.2 kg 4.2 kg 4.2 kg Wt of Mold 0.00094 0.00094 0.00094 | 0.00094 0.00094 Volume of mold (m3) B. Water Content Determination 1 3 4 Test Number 42.4 g 42.1 g 40.3 g 52.7 g 56.2 g Wt. of Container+ Wt. of wet soil 40.9 g 39.9 g 37.7 g 47.0 g 48.8 g Wt. of Container+ Wt. of dry soil 14.5 g 14.6 g 13.7 g 12.9 g 14.0 g Wt. of Container a. Compute the max. Dry unit in KN/m3 b. Compute the optimum water content in % c. Compute the degree of saturation at the optimum moisture content if the specific gravity of soil is 2.70. Plot moisture content versus dry unit weight.
The data from a standard Proctor test are shown in the table below.a. Determine the maximum dry unit weight and the optimum water content.b. Plot the zero air voids line.c. Determine the degree of saturation at the maximum dry unit weight.Diameter of mold 101.4 mmHeight of mold 116.7 mmMass of mold 4196.50 gramsSpecific gravity, Gs 2.722
type, d) QA. (5 Marks) Sieve analysis test on 400 gm of sand was conducted with the fo lowing records; Sieve No. 8 14 28 35 70 100 200 pan 2.362 1.168 0.589 0.417 0.295 0.147 0.074 Diameter (mm) Mass retained (gm) 60 100 72 48 62 18 30 A 60 160 B 280 342 360 390 C Total Retained (gm) % finer 85 60 42 30 D 10 2.5 a. What of the values of A, B, C and D. b. Determine the grading characteristics of this soil. c. Classify this soil according to its gradation using USCS method
the following data have been obtained in a standard laboratory proctor compaction test : Trial No. moisture content. % 1 9 2 3 4 6 11.9 14.6 15-8 19.0 21.6 weight of container and compacted soil 137.43 38.16 38-67 38-8439-06 38.76 (N) The container is 943 cm³ ih volume and its weight is 201 A-Determine the optimum moisture content and the maximum dry unit weight B-what is the dry uhit weight and water content at 95% standard compaction in the field ?
Task 1. Compaction test Table 1 Results of compaction test Run No Mass of sample and cylinder (g) Mass of cylinder (g) Can No Tare mass (g) Wet mass gross (g) Dry mass gross (g) 3 4 5 6022 6052 6102 6074 6015 4200 4200 4200 4200 4200 12 08 F3 F4 F5 31.12 31.04 31.31 30.83 31.53 80.17 97.9 93.68 84.28 108.81 79.07 95.71 89.93 79.91 101.29 Table 1 shows the results of compaction test on soil sample. (1) Describe the test procedure of compaction test. (2) Calculate water content and dry density in each run. (3) Plot the dry density-water content curve and zero air void line. (4) Determine the maximum dry density and optimum water content.
• Problem 2--- From the following data of the grain size analysis Sieve size #4 #8 #10 #25 #60 #100 # 200 Pan Sieve opening (mm) 4.76 2.36 2.00 0.71 0.25 0.149 0.074 Determine; a) Cu and Cc system % Finer (by weight) 80 56 51 35 18 13 7 ——— b) classify the soil using the unified soil classification
no Sieve analysis test on 400 gm of sand was conducted with the following records; Sieve No. 8 14 28 35 70 100 200 pan 2.362 1.168 0.589 0.417 0.295 0.147 0.074 M Diameter (mm) Mass retained (gm) 60 100 72 48 62 18 30 A 60 160 B 280 342 360 390 Total Retained (gm) % finer 85 60 42 30 D 10 2.5 a. What of the values of A, B, C and D. b. Determine the grading characteristics of this soil. c. Classify this soil according to its gradation using USCS method. C
Q3. A 1200 g sample of Gravel in the SSD condition in air and weighed 770 g when immersed in water. Also, a 500 g sample of Sand in the SSD condition in air and weighed 300 g when immersed in water Calculate the BSG(SSD) of the sand and gravel 1) the BSG (SSD) of the Gravel * 1.2.791 2.4.71 3.3.703 4.2.50 2) the BSG (SSD) of the Sand * 1.2.221 2.3.590 3.2.500 4.3.232 Choose one answer and write the answer number for me