The short beam shown in Fig. P6.9 cantilevers from a supporting column at the left. It must carry a calculated dead load of 2.0 kips/ft including its own weight and a service live load of 2.6 kips/ft. Tensile flexural reinforcement consists of two No. 11 (No. 36) bars at a 21 in. effective depth. Transverse No. 3 (No. 10) 2 No. 11 (No. 36) 2" clear- 3" clear - 21" 24" 20" -. 96" 18" U stirrups with 1.5 in. cover are provided at the following spacings from the face of the column: 4 in., 3 at 8 in., 5 at 10.5 in. (a) If the flexural and shear steel use f, = 60,000 psi and if the beam uses lightweight concrete having f, = 4000 psi, check to see if proper develop- ment length can be provided for the No. 11 (No. 36) bars. Use the simpli- fied development length equations. (b) Recalculate the required development length for the beam bars using the basic Eq. (6.4). Comment on your results. (c) If the column material strengths are f, = 60,000 psi and f. = 5000 psi (nor- malweight concrete), check to see if adequate embedment can be provided within the column for the No. 11 (No. 36) bars. If hooks are required, specify detailed dimensions.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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The short beam shown in Fig. P6.9 cantilevers from a supporting column at the
left. It must carry a calculated dead load of 2.0 kips/ft including its own weight
and a service live load of 2.6 kips/ft. Tensile flexural reinforcement consists
of two No. 11 (No. 36) bars at a 21 in. effective depth. Transverse No. 3 (No. 10)
2 No. 11 (No. 36)
2" clear-
3" clear
21" 24"
- 20" -
96"
- 18" -
U stirups with 1.5 in. cover are provided at the following spacings from the
face of the column: 4 in., 3 at 8 in., 5 at 10.5 in.
(a) If the flexural and shear steel use fy = 60,000 psi and if the beam uses
lightweight concrete having f' = 4000 psi, check to see if proper develop-
ment length can be provided for the No. 11 (No. 36) bars. Use the simpli-
fied development length equations.
(b) Recalculate the required development length for the beam bars using the
basic Eq. (6.4). Comment on your results.
(c) If the column material strengths are f, = 60,000 psi and f' = 5000 psi (nor-
malweight concrete), check to see if adequate embedment can be provided
within the column for the No. 11 (No. 36) bars. If hooks are required,
specify detailed dimensions.
Transcribed Image Text:The short beam shown in Fig. P6.9 cantilevers from a supporting column at the left. It must carry a calculated dead load of 2.0 kips/ft including its own weight and a service live load of 2.6 kips/ft. Tensile flexural reinforcement consists of two No. 11 (No. 36) bars at a 21 in. effective depth. Transverse No. 3 (No. 10) 2 No. 11 (No. 36) 2" clear- 3" clear 21" 24" - 20" - 96" - 18" - U stirups with 1.5 in. cover are provided at the following spacings from the face of the column: 4 in., 3 at 8 in., 5 at 10.5 in. (a) If the flexural and shear steel use fy = 60,000 psi and if the beam uses lightweight concrete having f' = 4000 psi, check to see if proper develop- ment length can be provided for the No. 11 (No. 36) bars. Use the simpli- fied development length equations. (b) Recalculate the required development length for the beam bars using the basic Eq. (6.4). Comment on your results. (c) If the column material strengths are f, = 60,000 psi and f' = 5000 psi (nor- malweight concrete), check to see if adequate embedment can be provided within the column for the No. 11 (No. 36) bars. If hooks are required, specify detailed dimensions.
ΔΤ
v =
byAx
V
(6-4)
bujd
Transcribed Image Text:ΔΤ v = byAx V (6-4) bujd
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