The sieve analysis, and the liquid and plastic limits of the four soils are given below. Using the AASHTO soil classification system, Plasticity for the soil passing No. Sieve Analysis; %Finer Soil 40 No. 10 No. 40 No. 200 Liquid Limit Plasticity Index A 83 48 20 20 100 92 86 70 32 48 28 D 90 76 34 What is the soil classification of soil A? O A-2 (0) O None of the choices. O A-1-b (0) O A-3 (0) O A-1-a (0)

The sieve analysis, and the liquid and plastic limits of the four soils are given below. Using the AASHTO soil classification system, Plasticity for the soil passing No. Sieve Analysis; %Finer Soil 40 No. 10 No. 40 No. 200 Liquid Limit Plasticity Index A 83 48 20 20 100 92 86 70 32 48 28 D 90 76 34 What is the soil classification of soil A? O A-2 (0) O None of the choices. O A-1-b (0) O A-3 (0) O A-1-a (0)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Classify the soil using USCS for the data given: Sieve Size 4.75 mm, weight retained 20 g; Sieve Size 0.075 mm, weight retained 730 g; 1000 g of soil was used. LL=40 and PL= 18. What is the classification of soil. a. SM b. SC c. SC-SM d. GC
Laboratory tests performed on a saturated alluvial subgrade soil gave the following information: In situ water content = 11.9%, Specific gravity = 2.65, Soil size distribution: D100 = 51 mm, D75 = 30 mm, D60 = 20 mm, D45 = 15 mm, D30 = 8 mm, D10 = 4.76 mm, D8 = 2 mm, D4 = 0.08 mm, < 2 m = 4% a. Is this soil well graded? Classify it by the AASHTO and Unified systems b. Using the sieve analysis soil data and the classification systems, estimate for a total of 100% the approximate percentages of coarse aggregate (gravel), fine aggregate (sand), silts, and clays?
Q 03: (a) Draw graph (using graph paper or excel) for soil 1 and 2 given in problem 2 and paste it in the following?(b) Calculate D10 D30 and D60 for Sieve Analysis plot in section (a) and calculate Coefficient of Uniformity and Coefficient of curvature for both soils. Also comment if the soils are well graded or poorly graded and which soil is better graded in comparing to other in case of soil 1 and 2.
Classify the group index of the soil by AASHTO Classification System using the given data below: Percent finer than the #10 sieve 100 Percent finer than the #40 sieve 92 Percent finer than the #200 sieve 86 Liquid Limit 70 Plasticity Index 32 Group of answer choices 24 16 0 33
soil mechanic. Classify the soil according to unified soil classification system USCS; if the following data is given : Passing sieve No. 200 =7% / Passing sieve No. 4 = 40% / D10= 0.18, D30= 0.69 and D60= 3/ LL-28%, Pl=19%
The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58.The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by USCS system a. CH b. SP-SC c. CL-ML d. CL-ML
Calculate the coefficient of gradation, Cc. ? Classify the soil by AASHTO and USCS system. (LL = 30, PL = 10) ? Use this given M=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 gM=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 g Sieve No. Opening Size (mm) Mass retained (g) %Mass retained=MiM×100=MiM×100 %Cumulative mass retained % Finer 4 4.750 28 =28617×100%=4.54%=28617×100%=4.54% 4.54 95.46 10 2.0 42 =42617×100%=6.81%=42617×100%=6.81% 11.35 88.65 20 0.850 48 =48617×100%=7.78%=48617×100%=7.78% 19.13 80.87 40 0.425 128 =128617×100%=20.74%=128617×100%=20.74% 39.87 60.13 60 0.250 221 =221617×100%=35.82%=221617×100%=35.82% 75.69 24.31 100 0.150 86 =86617×100%=13.94%=86617×100%=13.94% 89.63 10.37 200 0.075 40 =40617×100%=6.48%=40617×100%=6.48% 96.11 3.89 Pan 24 =24617×100%=3.89%=24617×100%=3.89% 100 0 Now, to plot the GSD curve, the % finer is kept on the vertical axis and the opening size are kept on the horizontal axis -…
From the data of grain size analysis; determine the following: a) coefficient of uniformity. b) Classify the soil using USCS. c.) Classify the soil using AASHTO LL=30% PI=25%
Soil Mechanics Based on the sieve analysis a soil has % finer for the following sieves: No. 10- 90% ; No. 40- 74% and No. 200- 58%. The liquid limit is 38 and Plasticity index is 12. Classify the soil by AASHT0 classification and give also the group index. a. A-6 (9) b. A-7-5(8) c. A-7-6(8) d. A-6 (5)
Afine-grainedsoilisfoundtohavealiquidlimitof70%andaplasticlimitof38%. (a) On the plasticity chart for the Unified Soil Classification System, what soil type is this?(b) On the plasticity chart for the AASHTO classification system, what soil type is this?
The following soil as specified by the AASHTO System has the following results:Percent finer than No. 10 sieve . . . . . . . . . . . . . 90Percent finer than No. 40 sieve . . . . . . . . . . . . . . 76Percent finer than No. 200 sieve . . . . . . . . . . .. . 34Liquid limit = 37Plasticity index = 12Calculate the partial group index for the soil that belongs to groups A-2-6.
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 73 No. 8 2.380 55 No. 10 2.000 49 No. 20 0.840 48 No. 40 0.420 45 No. 60 0.250 36 No. 100 0.150 29 No. 200 0.075 24 Characteristics of No. 40 Fraction LL -- PL -- A. A-2-4(0) B. A-3(0) C. A-2-5(0) D. A-1-a(0) E. A-1-b(0)