The simply supported beam consists of a W21 × 44 structural steel wide-flange shape [E = 29,000 ksi; I = 843 in.4]. Assume d = 5 ft, w = 3 kips/ft, P = 48 kips. For the loading shown, determine   (a) the beam deflection at point A. (b) the beam deflection at point C.

Q: 30k 10h 20 Fised Fised Fised 30

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Q: A beam ABCD is simply supported at ends 'A' and 'B' is loaded as shown in figure. Taking E= 2 x 105…

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Q: For the beam and loading shown, use the double-integration method to determine (a) the equation of…

A: ∑Ma=0⇒Cy*6-9*3*1.5=0                  ⇒Cy=6.75 KN∑Fy=0 ⇒Ay+Cy-9*3=0                 ⇒Ay=20.25 KN

Q: D

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Q: The beam supports the loads as shown in the figure. Using E=200 GPa, w = 21 kN/m, P = 35 and M = 28…

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Q: B. Determine the slope and displacement at the end C of the beam E = 200GPA, I = 70(10*) mm". Use…

A: Given data, Modulus of elasticity, E=200GPa MOI, I=70×106 mm4 EI=200×103×70×106EI=1.4×1013…

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Q: w kN/m M kN.m В А D C L 2L 2L F kN Xf Yf E Yg Xg Yf Xf

A: It is required to find 1.A- normal force at C 1.B- shear force at C 1.C- bending moment at C

Q: B AM

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A: We will find vertical component of actual deformation.

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Q: Using portal method, solve for the following member forces; a. Axial force on member CD in kN. b.…

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Q: 12 kN P N. 12 kN 4 m M 32 kN K F 14m Н. 6 m A BX DX E 4. i. 16 m 10 m -- 10 m- 16 m

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A: RA+RB= 0.5 x 3 x 5 +11 = 18.5 kN Moment about A MA=0 -7.5 x 2 - 11 x 4 -22 +RD x 5 =0 or, RD= 16.2…

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Q: F, D E G X -

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Q: Determine the horizontal displacement of joint A. Each bar is made of A992 steel and has a…

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Q: The beam supports the loads as shown in the figure. Using E = 200 GPa, w = 16KN/m, P= 16KN and M=…

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Q: Determine the slope and the displacement at the end C of the beam. E = 200 GPa, I = 70(10) mm*.

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Q: Question 1) F=22 kN single load, M-24 kN.m moment and w=5 kN/m distributed load act on the beam…

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Q: Compute the maximum bending moment of the given beam below. (kN-m) Note: Use two (2) decimal places…

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Q: For the beam shown, draw the conjugate beam and show values. 20 kN/m EI 2 m 2E1 4m C

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Q: 10. The rigid bar AB, attached to aluminum and Steel steel rods, Aluminum L=3 m A = 300 mm2 E= 70…

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Q: 2. The beam shown has a rectangular cross section 4 inches wide by 8 inches deep. Compute the value…

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Q: The plane, pin-jointed frame shown in Figure QA5 consists of two steel members, each with a…

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Q: length and a concentrated load of 800 N 1 meter from the left support. The cross-sectional area of…

A: Find reactions :∑ MB=0RA(4)-12(4)(2)-0.8(2)=0RA=24.4NRB=24.4N

Q: Rigid

A:

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.